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choli [55]
2 years ago
6

Which statement is an example of the symmetric property of congruence?

Mathematics
2 answers:
Anna35 [415]2 years ago
7 0
The answer is D. The symmetric property of congruence basically just states that if A is congruent to B, then B is congruent to A. This is like symmetry or a mirror, thus giving it it's name.
olchik [2.2K]2 years ago
3 0

The symmetric property of congruence states that if a quantity, say, A is congruent to a quantity, say B, then, the quantity B is congruent to the quantity A.

Mathematically, this statement of the symmetric property of congruence can be written as:

If A\cong B, then B\cong A.

Applying this symmetric property of congruence to the question that we are given, we see that only Option D fulfills the conditions of the definition of the property of congruence as Option D clearly states that:

If \Delta EFG\cong \Delta HJK, then \Delta HJK\cong \Delta EFG which is the exact statement of the symmetric property of congruence when applied to triangles.

Thus, Option D is the correct option.

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Marissa is ordering Negative one-sixth, negative one-third, 1.4, 0.2, two-thirds from least to greatest. Here are her steps:
Effectus [21]

Step-by-step explanation:

no 2

if wrong correct me pls

6 0
2 years ago
A teacher decides to purchase a new car and considers two options. Option one is the new Zoomba for $60,000 with an expected dep
kupik [55]

Answer:

She chose Option 2 which is a linear option, because it offers a smaller lose    

in value compared to option 1 which is an exponential option.

The final value for option 2=$32,800

Step-by-step explanation:

Option 1

New Zoomba for 60000 with a depreciation rat of 2%per month for 3 years

Exponential equation;

y=a(1-r)^t

where;

y=future value

a=initial value=60000

r=depreciation rate=2% per month

t=time interval=12×3=36 months

Replacing;

y=60000(1-2/100)^36

y=60000(0.98)^36=28,992.79

The value after 3 years=$28,992.79

Initial value-Final value=(60000-28992.79)=$31007.21

Percentage of initial value lost=((Final value-Initial Value)/(Initial Value))×100

(31007.21/60000)×100=51.68%

Option 2

New starfish for $40,000 with a depreciation of $200 per month for 3 years

Linear equation;

y=a-bt

where;

y=Future value

a=Initial value=$40,000

b=the depreciation amount per time interval=$200 per month for 3 years

t=time interval=(3×12)=36 months

Replacing;

y=40000-(200×36)

y=32,800

Final value=y=$32,800

Initial value-Final value=(40000-32800)=$7200

Percentage of initial value lost=((Final value-Initial Value)/(Initial Value))×100

(7200/40000)×100=18%

Option 1(51.68%)>Option 2(18%) therefor Option 1 loses value at a faster rate than Option 2

She chose Option 2 which is a linear option, because it offers a smaller lose    

in value compared to option 1 which is an exponential option

4 0
2 years ago
Supervisor: "Last week, you spoke with 800 customers in 40 hours."
algol13

Answer:12

Step-by-step explanation:

0 0
2 years ago
I received a letter from your competitor that mentions a savings of 15% over your prices. Can you match this offer? My current r
exis [7]

Given my current rate = $129.00 per month.

Savings of 15% over your prices.

Therefore, saving = 15% of $129.00 = 0.15 × 129.00 =$19.35.

Adjusted rate = current rate - saving = 129 - 19.35 = $109.65

Therefore, We can rewrite above expression as :

My current rate is $129.00<u> </u><u>per month</u>." Representative: "We will match any competitive offer. Your adjusted rate will be <u>109.65 </u>dollars per month."


5 0
2 years ago
.580 80 repeating as fraction
denis-greek [22]
First off, we'll move the non-repeating part in the decimal to the left-side, by doing a division by a power of 10.

then we'll equate the value to some variable, and move the repeating part over to the left as well.

anyhow, the idea being, we can just use that variable, say "x" for the repeating bit, let's proceed,

\bf 0.580\overline{80}\implies \boxed{\cfrac{5.80\overline{80}}{10}}\qquad \textit{now, let's say }x= 5.80\overline{80}\\\\&#10;-------------------------------

\bf thus\qquad \begin{array}{llll}&#10;100\cdot x&=&580.80\overline{80}\\&#10;&&575+5.80\overline{80}\\&#10;&&575+x&#10;\end{array}\qquad \implies 100x=575+x&#10;\\\\\\&#10;99x=575\implies x=\cfrac{575}{99}\qquad therefore\qquad \boxed{\cfrac{5.80\overline{80}}{10}}\implies \cfrac{\quad \frac{575}{99}\quad }{10}&#10;\\\\\\&#10;\cfrac{\quad \frac{575}{99}\quad }{\frac{10}{1}}\implies \cfrac{575}{99}\cdot \cfrac{1}{10}\implies \cfrac{575}{990}\implies \stackrel{simplified}{\cfrac{115}{198}}

and you can check that in your calculator.
4 0
2 years ago
Read 2 more answers
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