Given : 79% (actual results are 400 out of 506 surveyed) of California adults feel that "education and our schools" is one of the top issues facing California.

i.e.Sample size : n= 506

Sample proportion : $\hat{p}=0.79$

Critical value for 90% confidence interval ( Using z-value table) :

$z=1.645$

Now, the 90% confidence interval for the population proportion will be :

$\hat{p}\pm z\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

i.e. $0.79\pm (1.645)\sqrt{\dfrac{0.79(1-0.79)}{506}}$

i.e. $0.79\pm (1.645)(0.0181)$

$\approx0.79\pm 0.030=(0.79-0.030,\ 0.79+0.030)\\\\=(0.760,\ 0.820)$

Hence, the 90% confidence interval for the population proportion= (0.760, 0.820)

7 0

2 years ago

How to write 12430000 in expanded form

Marrrta [24]

10,000,000+2,000,000+400,000+30,000

8 0

2 years ago

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A certain shade of green paint is made from 5 parts yellow mixed with three parts blue if 2 cans of yellow are used how many can

wariber [46]

Because the ratio of yellow to blue can be expressed as 5/3, you would solve the equation 5/3= 2/x. To solve, you would get x alone by cross multiplying and getting 5x=6. Divide both sides by 5 and get 6/5 or 1 and 1/5 cans of blue paint

5 0

2 years ago