Since the printer depreciates at a rate of 5% per year, I believe the stated equation is miss typed. Therefore I'll answer this with the correct equation that would represent that setting:

$y(x) = 25,000*0.95^x$

In the first year the value of the printer is:

$y(1) = 25,000*0.95^1 = 23,750$

On the second year the value of the printer is:

$y(2) = 25,000*0.95^2 = 22,562.5\\$

On the third year the value of the printer is:

$y(3) = 25,000*0.95^3 = 21,434.38\\$

The value of the printer on the first year was $ 23,750.00. On the second year it was $ 22,562.5. On the third year it was $ 21,434.38.

5 0

2 years ago

nicholas started a canned food drive at school. the equation representing this is y=235=15, where x is the number of days, and y

qwelly [4]

Answer:

195 cans will be left after 10 days

Sample Answer: I am given a number of cans, which is y, and I need to find the number of days, which is x. To do this, I would substitute 2600 for y, to get 2600 = 235x + 15. Solving for x, I would get x = 11. Thus, it would take 11 days to collect 2600 cans.

Step-by-step explanation:

i did the edge thing

6 0

2 years ago

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