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MakcuM [25]
2 years ago
6

Use Gauss's Law to find the charge contained in the solid hemisphere x2 + y2 + z2 ≤ a2, z ≥ 0, if the electric field is E(x, y,

z) = x i + y j + 6z k.
Mathematics
1 answer:
Anit [1.1K]2 years ago
6 0

Answer:<em><u> \frac{16}{3}πa^{3} . </u></em>

Given:

x^{2}+y^{2}+z^{2} \leq a^{2}, z \geq 0

Using Gauss's Law = ∫∫s E ·dS  

= ∫∫∫ div E dV,  

⇒ Divergence (Gauss') Theorem  

= ∫∫∫ (1+1+6) dV  

= 8×(volume of the hemisphere, radius "a")  

= 8× (\frac{1}{2})(4/3)πa^{3}  

<em><u>= \frac{16}{3}πa^{3} . </u></em>

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Triangle H N K is shown. Angle H N K is 90 degrees. The length of hypotenuse H K is n, the length of H N is 12, and the length o
Mazyrski [523]

Answer:

13

Step-by-step explanation:

From the question, we are given a triangle HNK with an angle of 90°

The length of hypotenuse H K is n,

the length of HN is 12

the length of N K is 6.

From the above values, obtained in the question, we can see that this is a right angled triangle.

We are asked to find the length of the hypotenuse.

We can use Pythagoras Theorem of solve for this.

c² = a² + b²

where c = HK = n

a = NK = 6

b = HN = 12

c² = 6² + 12²

c² = 36 + 144

c² = 180

c = √180

c = 13.416407865

Approximately to the nearest whole number = 13

Therefore the value of HK = n = 13

We can also use Law of Cosines as given in the question to solve for this.

a² = b² + c² - 2ac × Cos A

where c = HK = n

a = NK = 6

b = HN = 12

Hence

c² = a² + b² - 2ab × Cos C

c = √ (a² + b² - 2ab × Cos C)

Where C = 90

c = √ 6² + 12² - 2 × 6 × 12 × Cos 90

c = 13.42

Approximately to the nearest whole number ≈ 13

Therefore the value of HK = n = 13

8 0
1 year ago
If a plane can climb at 2,400 feet per minute, how many minutes are needed to climb to 60,000 feet?
fomenos

Answer:

b

Step-by-step explanation:

25 minutes

5 0
2 years ago
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Henry has quarters, dimes, nickels and pennies in a coin jar. He says that the total amount of money is two dollars and forty-on
Gala2k [10]

Answer: D

Step-by-step explanation:

All would add up to 241 instead of 2.41 because you are not using decimals for the constants (Example: 25q not .25q)

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2 years ago
A triangle has side lengths of (1.3k+3.5m)(1.3k+3.5m) centimeters, (4.1k-1.6n)(4.1k−1.6n) centimeters, and (9.7n+4.4m)(9.7n+4.4m
Scorpion4ik [409]

Answer:

(5.4k+7.9m+8.1n) centimeters

Step-by-step explanation:

Given the side length of a triangle;

S1 = (1.3k+3.5m) cm

S2 = (4.1k-1.6n) cm

S3 = (9.7n+4.4m) cm

Perimeter of the triangle = S1+S2 + S3

Perimeter of the triangle = (1.3k+3.5m) + (4.1k-1.6n) + (9.7n+4.4m)

Collect the like terms;

Perimeter of the triangle = 1.3k+4.1k+3.5m+4.4m-1.6n+9.7n

Perimeter of the triangle = 5.4k+7.9m+8.1n

Hence the expression that represents the perimeter of the triangle is (5.4k+7.9m+8.1n) centimeters

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2 years ago
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