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VARVARA [1.3K]
2 years ago
11

A Department of Transportation survey showed that 60% of U.S. residents over 65 years of age oppose use of cell phones in flight

even if there were no issues with the phones interfering with aircraft communications systems. If this information is correct and if a researcher randomly selects 25 U.S. residents who are over 65 years of age?
a. What is the probability that exactly 12 oppose the use of cell phones in flight?
b. What is the probability that more than 17 oppose the use of cell phones in flight?
c. What is the probability that less than eight oppose the use of cell phones in flight? If the researcher actually got less than eight,what might she conclude about the Department of Transportation survey?
Mathematics
1 answer:
Shalnov [3]2 years ago
4 0

Answer:

a) P(X=12)=(25C12)(0.6)^{12} (1-0.6)^{25-12}=0.0760

b) P(X>17) = P(X=18) +....+P(X=25)

And we can use the following excel code: "=1-BINOM.DIST(17;25,0.6,TRUE)"

And we got:

P(X>17) = P(X=18) +....+P(X=25)= 0.154

c) P(X

And using the following excel code we got: "=BINOM.DIST(7,25,0.6,TRUE)"

And we got:

P(X

Step-by-step explanation:

Previous concepts

A Bernoulli trial is "a random experiment with exactly two possible outcomes, "success" and "failure", in which the probability of success is the same every time the experiment is conducted". And this experiment is a particular case of the binomial experiment.

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

The probability mass function for the Binomial distribution is given as:  

P(X)=(nCx)(p)^x (1-p)^{n-x}  

Where (nCx) means combinatory and it's given by this formula:  

nCx=\frac{n!}{(n-x)! x!}  

The complement rule is a theorem that provides a connection between the probability of an event and the probability of the complement of the event. Lat A the event of interest and A' the complement. The rule is defined by: P(A)+P(A') =1

Solution to the problem

Part a

P(X=12)=(25C12)(0.6)^{12} (1-0.6)^{25-12}=0.0760

Part b

For this case we want this probability:

P(X>17) = P(X=18) +....+P(X=25)

And we can use the following excel code: "=1-BINOM.DIST(17,25,0.6,TRUE)"

And we got:

P(X>17) = P(X=18) +....+P(X=25)= 0.154

Part c

For this case we want this probability:

P(X

And using the following excel code we got: "=BINOM.DIST(7,25,0.6,TRUE)"

And we got:

P(X

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Nataly [62]

Answer:

b. The values X and Y are independent therefore, the mean is 34 seconds and the standard deviation is 50 seconds

Step-by-step explanation:

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When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

Before the training, the mean running time for the students to run a mile was 402 seconds with standard deviation 40 seconds.

This means that \mu_X = 402, \sigma_X = 40

After completing the program, the mean running time for the students to run a mile was 368 seconds with standard deviation 30 seconds.

This means that \mu_Y = 368, \sigma_Y = 30

Which of the following is true about the distribution of X-Y?

They are independent, so:

\mu = \mu_X - \mu_Y = 402 - 368 = 34

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This means that the correct answer is given by option b.

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Given that a 90% confidence interval for the mean height of all adult males in Idaho measured in inches was [62.532, 76.478]. Us
grigory [225]

Answer:

The confidence interval on this case is given by:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)

For this case the confidence interval is given by (62.532, 76.478)[/tex]

And we can calculate the mean with this:

\bar X = \frac{62.532+76.478}{2}= 69.505

So then the mean for this case is 69.505

Step-by-step explanation:

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Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

\bar X represent the sample mean  

\mu population mean (variable of interest)  

\sigma represent the population standard deviation  

n represent the sample size  

Assuming the X follows a normal distribution  

X \sim N(\mu, \sigma)

The confidence interval on this case is given by:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)

For this case the confidence interval is given by (62.532, 76.478)[/tex]

And we can calculate the mean with this:

\bar X = \frac{62.532+76.478}{2}= 69.505

So then the mean for this case is 69.505

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cluponka [151]

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Step-by-step explanation:

Since we have given that

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Angle between them = 50°

So,

We will use the "Cosine formula", we get

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Distance=\frac{Speed}{time}=\frac{230.65}{1}=230.65\ miles

So, the distance between them is 230.65 miles.

6 0
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rule of 70:

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x = 70/10 = 7%

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