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iogann1982 [59]
2 years ago
13

Your class started at 12:12PM and ended at 12:50PM. What angle did the minute hand of a watch sweep through during the class? A.

228. B. 132. C. 168. D. 153.
Mathematics
1 answer:
djverab [1.8K]2 years ago
8 0

recall that a circle has a total of 360°.


now the clock has 60 minutes, how many degrees are there between each minute? well, that'd be 360°/60, which gives us 6° for every passing minute.


the class started at 12:12, went through to 12:50, that's 38 minutes, and since every passing minute is 6°, that'd be 38 * 6.

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Evaluate sin(Arcos(-9/√145)).
tino4ka555 [31]

Use the fact that \sin x = \sqrt{1-\cos^2 x} to solve it.

\sin(\arccos(-\frac{9}{\sqrt{145}}))=\sqrt{1-\cos^2(\arccos(-\frac{9}{\sqrt{145}}))} =\\= \sqrt{1-(-\frac{9}{\sqrt{145}})^2}=\frac{8}{\sqrt{145}}

8 0
2 years ago
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At 4 p.m., the temperature started to change drastically. Each hour, for three hours, the temperature decreased by 7°F. Which wo
nasty-shy [4]

Answer:

Decreased.

Step-by-step explanation:

Decrease means to go down or take away, therefore in a mathematical equation, it would be represented by a negative integer.

Change could be positive or negative

each is a singular description word

and drastically is just describing how fast.

have a good day!

6 0
2 years ago
Write the equation of the line that is parallel to the line y=-7/4x-2 through the point (4,2)! Help please
Sladkaya [172]

as you already know, the equation y=-7/4x-2, is already in slope-intercept form and thus its slope is the coefficient of the "x", namely -7/4.

parallel lines have the same exact slope, so a parallel line to this one will also have a slope of -7/4, and it passes through 4,2,

\bf (\stackrel{x_1}{4}~,~\stackrel{y_1}{2})\qquad \qquad \qquad  slope =  m\implies -\cfrac{7}{4} \\\\\\ \stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-2=-\cfrac{7}{4}(x-4) \\\\\\ y-2=-\cfrac{7}{4}x+7\implies y=-\cfrac{7}{4}x+9

6 0
2 years ago
A portfolio has average return of 13.2 percent and standard deviation of returns of 18.9 percent. Assuming that the portfolioi's
wlad13 [49]

Answer:

B. 0.835

Step-by-step explanation:

We can use the z-scores and the standard normal distribution to calculate this probability.

We have a normal distribution for the portfolio return, with mean 13.2 and standard deviation 18.9.

We have to calculate the probability that the portfolio's return in any given year is between -43.5 and 32.1.

Then, the z-scores for X=-43.5 and 32.1 are:

z_1=\dfrac{X_1-\mu}{\sigma}=\dfrac{(-43.5)-13.2}{18.9}=\dfrac{-56.7}{18.9}=-3\\\\\\z_2=\dfrac{X_2-\mu}{\sigma}=\dfrac{32.1-13.2}{18.9}=\dfrac{18.9}{18.9}=1\\\\\\

Then, the probability that the portfolio's return in any given year is between -43.5 and 32.1 is:

P(-43.5

6 0
2 years ago
A car’s momentum is p when it is traveling with a velocity of v. If the velocity of that car doubles, what is the new momentum o
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P = mv

p and v are directly related. If the velocity is doubled then so is the momentum..
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