Jake spent a total of 70 cents.
b = black-and-white = 8 cents
c = color = 15 cents
70 = 8b + 15c
he made a total of 7 copies
b + c = 7
system of equation:
70 = 8b + 15c
b + c = 7
--------------------------
b + c = 7
b + c (-c) = 7 (-c)
b = 7 - c
plug in 7 - c for b
70 = 8(7 - c) + 15c
Distribute the 8 to both 7 and - c (distributive property)
70 = 56 - 8c + 15c
Simplify like terms
70 = 56 - 8c + 15c
70 = 56 + 7c
Isolate the c, do the opposite of PEMDAS: Subtract 56 from both sides
70 (-56) = 56 (-56) + 7c
14 = 7c
divide 7 from both sides to isolate the c
14 = 7c
14/7 = 7c/7
c = 14/7
c = 2
c = 2
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Now that you know what c equals (c = 2), plug in 2 for c in one of the equations.
b + c = 7
c = 2
<em>b + (2) = 7
</em><em />Find b by isolating it. subtract 2 from both sides
b + 2 = 7
b + 2 (-2) = 7 (-2)
b = 7 - 2
b = 5
Jake made 5 black-and-white copies, and 2 color copies
hope this helps
Answer:
0.2163
Step-by-step explanation:
Firstly, we need to evaluate the total number of possible outcomes. Since there are 16 players, and we are selecting just 5, the total number of possibilities is 16C5= 4,368
Now, we know we need 2 guards from 6 , 2 forwards from 7 and 1 center from 3 to start the game. Since we are selecting, it is a combination problem. These can be done in the following number of ways:
6C2 * 7C2* 3C1
The probability is thus (6C2 * 7C2* 3C1 )/16C5 = 945/4368 = 0.2163
June :
900 + 0.02(48,500) + 0.018(48500 - 17500) =
900 + 970 + 558 = 2428 <==
July :
900 + .02(50,200) + 0.018(50200 - 17500) =
900 + 1004 + 588.60 = 2492.60 <===
Answer:
Here we have given two catogaries as degree holder and non degree holder.
So here we have to test the hypothesis that,
H0 : p1 = p2 Vs H1 : p1 not= p2
where p1 is population proportion of degree holder.
p2 is population proportion of non degree holder.
Assume alpha = level of significance = 5% = 0.05
The test is two tailed.
Here test statistic follows standard normal distribution.
The test statistic is,
Z = (p1^ - p2^) / SE
where SE = sqrt[(p^*q^)/n1 + (p^*q^)/n2]
p1^ = x1/n1
p2^ = x2/n2
p^ = (x1+x2) / (n1+n2)
This we can done in TI_83 calculator.
steps :
STAT --> TESTS --> 6:2-PropZTest --> ENTER --> Input all the values --> select alternative "not= P2" --> ENTER --> Calculate --> ENTER
Test statistic Z = 1.60
P-value = 0.1090
P-value > alpha
Fail to reject H0 or accept H0 at 5% level of significance.
Conclusion : There is not sufficient evidence to say that the percent of correct answers is significantly different between degree holders and non-degree holders.
Answer:
= {2, 4, 10}
Step-by-step explanation:
A set is a collection of objects called elements. These element are refered to as members of the set.
Set A contains all integers from 1 to 10 inclusive;
A = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}
A subset of a given set implies that every element of the subset are also elements of the given set. Set B is a subset of A;
B = {1, 3, 5, 6, 7, 8, 9}
Complement of a given set refers to elements not in the general set. Set C is the complement of B;
= {2, 4, 10}
