Answer:
Pr(X>1540.2) = 0.0655
Step-by-step explanation:
Expected value of large bottle,
E(Large) = 1016
Expected value of small bottle,
E(small) = 510
Expected value of total
E(total) = 1016 + 510 = 1526
So the new mean is 1526
Find standard deviation of new amount by variance
Variance of large bottle,
v(large) = 8^2 = 64
Variance of small bottle,
v(small) = 5^2 = 25
Variance of total
v(total) = 64+25 = 89
So the new standard deviation
sd(new) = sqrt(89) = 9.434
Find probability using the new mean and s.d.
Pr(X>1540.2)
Z score, z = (x-mean)/sd
= (1540.2 - 1526)/9.434
= 1.505
value in z score
P(z<1.51) = 0.9345
For probability of x > 1540.2
P(z > 1.51) = 1 - 0.9345 = 0.0655
What values of b satisfy 3(2b+3)^2 = 36
we have
3(2b+3)^2 = 36
Divide both sides by 3
(2b+3)^2 = 12
take the square root of both sides
( 2b+3)} =(+ /-) \sqrt{12} \\ 2b=(+ /-) \sqrt{12}-3
b1=\frac{\sqrt{12}}{2} -\frac{3}{2}
b1=\sqrt{3} -\frac{3}{2}
b2=\frac{-\sqrt{12}}{2} -\frac{3}{2}
b2=-\sqrt{3} -\frac{3}{2}
therefore
the answer is
the values of b are
b1=\sqrt{3} -\frac{3}{2}
b2=-\sqrt{3} -\frac{3}{2}
Answer:
The domain of the function is all real numbers
and the range is all positive real numbers 
Step-by-step explanation:
We have the following function
and we want to find the domain and the range.
The function we have is an example of an exponential function
with b > 0 and b ≠ 1. This types of functions in general have the following properties:
- It is always greater than 0, and never crosses the x-axis
- Its domain is the set of real numbers
- Its Range is the Positive Real Numbers

The domain of a function is the specific set of values that the independent variable in a function can take on.
When determining domain it is more convenient to determine where the function would not exist.
This function has no undefined points nor domain constraints. Therefore the domain is
.
The range is the resulting values that the dependent variable can have as x varies throughout the domain. Therefore the range is
.
We can check our results with the graph of the function.