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2 years ago

. James has 16 ounces (oz.) of cookie dough. If he uses 0.56 oz. of cookie dough for each

Mathematics

2 answers:

Citrus2011 [14]2 years ago

8 0

Answer:

Step-by-step explanation:

No. of cookies James can make = (16/0.56) cookies

= 28.5714 cookies

= which is approximately 30 cookies

Hope this helps!

Anna71 [15]2 years ago

6 0

Step-by-step explanation:

Step 1: Find the reasonable estimate

$Total\ Amount\ of\ Dough / Dough\ Per\ Cookie$

$16 / 0.56$

$28.571...$

The closest number to 28 out of the option is 30. Therefore, the correct option is D.

Answer: Option D

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the scale on a map is stated as 1:250000 two villages are 9 cm apart on the map how far from each other are the two villages in

Karolina [17]

Answer:

22.5 kilometers

Step-by-step explanation:

we know that

The scale drawing is

$1:250,000$

That means

1 unit on a map represent 250,000 units in the actual

1 cm on a map represent 250,000 cm in the actual

1 cm on a map represent 2,500 m in the actual

1 cm on a map represent 2,5 km in the actual

therefore

using proportion

Find out how much represent 9 cm apart on the map

$\frac{1}{2.5}\ \frac{cm}{km}=\frac{9}{x}\ \frac{cm}{km}\\\\x=9(2.5)\\\\x=22.5\ km$

7 0

2 years ago

The following two sets of parametric functions both represent the same ellipse. Explain the difference between the graphs.

statuscvo [17]

The answer
ellipse main equatin is as follow:

X²/ a² + Y²/ b² =1, where a≠0 and b≠0

for the first equation: x = 3 cos t and y = 8 sin t
we can write x² = 3² cos² t and y² = 8² sin² t
and then x² /3²= cos² t and y²/8² = sin² t
therefore, x² /3²+ y²/8² = cos² t + sin² t = 1
equivalent to x² /3²+ y²/8² = 1

for the second equation, x = 3 cos 4t and y = 8 sin 4t we found
x² /3²+ y²/8² = cos² 4t + sin² 4t=1

7 0

2 years ago

Read 2 more answers

Two cross sections of a right hexagonal pyramid are obtained by cutting the pyramid with planes parallel to the hexagonal base.

Tanya [424]

Answer:

The larger cross section is 24 meters away from the apex.

Step-by-step explanation:

The cross section of a right hexagonal pyramid is a hexagon; therefore, let us first get some things clear about a hexagon.

The length of the side of the hexagon is equal to the radius of the circle that inscribes it.

The area is

$A=\frac{3\sqrt{3} }{2} r^2$

Where $r$ is the radius of the inscribing circle (or the length of side of the hexagon).

Now we are given the areas of the two cross sections of the right hexagonal pyramid: $A_1=216\:ft^2\: \:\:\:A_2=486\:ft^2$

From these areas we find the radius of the hexagons:

$r_1=\sqrt{\frac{2A_1}{3\sqrt{3} } } =\sqrt{\frac{2*216}{3\sqrt{3} } }=\boxed{9.12ft}$

$r_2=\sqrt{\frac{2A_2}{3\sqrt{3} } } =\sqrt{\frac{2*486}{3\sqrt{3} } }=\boxed{13.68ft}$

Now when we look at the right hexagonal pyramid from the sides ( as shown in the figure attached ), we see that $r_1$ $r_2$ form similar triangles with length $H$