Answer:
Step-by-step explanation:
a) ΔACD ~ ΔABE so the ratios of corresponding sides are the same. That is ...
CD/BE = CA/BA
CD/3.8 = 12.3/8.2
CD = 3.8×12.3/8.2 = 5.7 . . . . cm
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b) As above, the ratios of corresponding sides are the same.
ED/AD = BC/AC
ED/9.15 = (12.3-8.2)/12.3 . . . . BC = AC - AB
ED = 9.15×4.1/12.3 = 3.05 . . . . cm
We assume all employees are either full-time or part-time.
36 = 24 + 12
If the number of full-time employees is 24 or less, the number of part-time employees must be 12 or more. (Thinking, based on knowledge of sums.)
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You can write the inequality in two stages.
- First, write and solve an equation for the number of full-time employees in terms of the number of part-time employees.
- Then apply the given constraint on full-time employees. This gives an inequality you can solve for the number of part-time employees.
Let f and p represent the numbers of full-time and part-time employees, respectively.
... f + p = 36 . . . . . . given
... f = 36 - p . . . . . . . subtract p. This is our expression for f in terms of p.
... f ≤ 24 . . . . . . . . . given
... (36 -p) ≤ 24 . . . . substitute for f. Here's your inequality in p.
... 36 - 24 ≤ p . . . . add p-24
... p ≥ 12 . . . . . . . . the solution to the inequality
Answer:
15.6%
Step-by-step explanation:
Since each day there is a 6% chance that Lisa smiles at him then that means that each day there is a 94% chance that Lisa does not smile at him. To find the probability of Milhouse going longer than a month (30 days) without a smile from Lisa we need to multiply this percentage in decimal form for every day of the month. This can be solved easily by putting 94% to the 30th power which would be the same, but first, we need to turn it into a decimal...
94% / 100 = 0.94
= 0.156
Now we can turn this decimal into a percentage by multiplying by 100
0.156 * 100 = 15.6%
Finally, we can see that the probability that Milhouse goes longer than a month without a smile from Lisa is 15.6%
They are called invertebrats
Given differential equation, (D4 - 5D3 + 5D2 + 5D - 6)y = 0
=> For general solution of equation,
Solve D4 - 5D3 + 5D2 + 5D - 6 = 0
=> D4 - 5D3 + 6D2 - D2 + 5D - 6 = 0
=> D2 (D2 - 5D + 6) - (D2 - 5D + 6) = 0
=> (D2 - 5D + 6)(D2 - 1) = 0 ................................(1)
Now
D2 - 1 = (D - 1)(D + 1) and
Factors of D2 - 5D + 6
D2 - 5D + 6 = D2 - 2D - 3D + 6
= D(D - 2) - 3(D - 2)
= (D - 3)(D - 2)
Therefore, equation (1) implies
(D2 - 5D + 6)(D2 - 1) = (D - 3)(D - 2)(D - 1)(D + 1) = 0
=> D = 3, 2, 1, -1 or D = -1, 1,, 2, 3
=> General solution of differential equation is,<span>
=><span> y = C1 e-x + C2 ex + C3 e2x + C4 e3x</span> .
Hope it helps
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