Answer:
A. 57 mL/hr
Step-by-step explanation:
Mass of morphine sulfate = 125 mg
DW = 250 mL
Rate of infusion = 0.005 mg/kg/min
Converting to mg/kg/hour
0.005 mg/kg/min×60 = 0.3 mg/kg/hour
For the patient who weighs 95 kilograms
0.3 mg/kg/hour×95 = 28.5 mg/hour
For the mass of 125 mg of morphine sulfate
1 mg
250/150 = 2 ml/mg
Rate of infusion
28.5×2 = 57 mL/hr
∴ Rate of infusion is 57 mL/hr
<span>$1750 * 0.019 = $33.25
interest earned first year was $33.25
answer is </span><span>B: $33.25</span>
Given the conditional relative frequency table below which was generated by
column using frequency table data comparing the number of calories in a meal to
whether the meal was prepared at home or at a restaurant.
Number of Calories and Location of Meal Preparation.
Home Restaurant Total
≥ 500 calories 0.15 0.55 0.28
< 500 calories 0.85 0.45 0.72
Total 1.0 1.0 1.0
To determine whether there is an association between where food is prepared and the number of carories the food contain, we recall that an "association" exists between two categorical variables if the column conditional relative frequencies are different
for the columns of the table. The bigger the differences in
the conditional relative frequencies, the stronger the association
between the variables. If the conditional relative frequencies are
nearly equal for all categories, there may be no association between the
variables. Such variables are said to be <span>independent.
For the given conditional relative freduency, we can see that there is a significant difference between the columns of the table.
i.e. 0.15 is significantly different from 0.55 and 0.85 is significantly different from 0.45
Therefore, we can conclude from the given answer options that t</span><span>here is an association because the value 0.15 is not similar to the value 0.55</span>
Hiii
all you do is subtract...
534-476=58
58 spots are left.
Answer:
1800
Step-by-step explanation:
Labor quantity variance= Actual quantity ×standard price - standard quantity ×standard price
Standard quantity=2×2600=5200
Labor quantity variance
5050×12-5200×12=1800
