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1 year ago

Segmented animals without a backbone are called?

Mathematics

2 answers:

DENIUS [597]1 year ago

7 0

Answer:

invertebrates

Step-by-step explanation:

puteri [66]1 year ago

3 0

They are called invertebrats

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Christina will be retiring next month from her job after 35 years as a school bus driver. Over the last 35 years, Christina’s an

HACTEHA [7]

Given: Annual salary average: $22,040 Annual Social security benefit: 42% of salary average Monthly bill: $1,375 $22,040 x 42% = $9,256.80 per annum $9,256.80 / 12 mos = $771.40 per month $1,375 – 771.40 = $603.60 Since, Christina only receives $771.40 per month from her Social Security benefit, she has to take $603.60 from her savings each month to help pay her monthly bill of $1,375. <span>
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1 year ago

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60% of the students in Mr. Vick's class have computers at home. If 21 students in his class have computers at home, how many stu

aleksley [76]

Answer:

There are 35 students in his class.

Step-by-step explanation:

1. Create a proportion: 60/100=21/x

2. Cross multiply, or not (I prefer to cross multiply). 60x=2100

3. Solve the equation: x=35.

Answer: There are 35 students in his class, 14 people going in school, 21 student online.

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1 year ago

Tyler had $65.40 in his checking account. Then he wrote checks on the account for $20.38, $11.48, and $19.50. What is the balanc

andrew-mc [135]

money going out (20.38+11.48+19.50) =51.36

balance - out = new balance

65.40-51.36 =

14.04

new balance = 14.04

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2 years ago

A group of astronomers observed light coming from a star located a distance of 331,000,000,000,000,000,000,000,000 light-years f

Anika [276]

3.31 times 10 to the 26th power

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1 year ago

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A karate center has 120 students. The director wants to set a goal to motivate her instructors to increase student enrollment. U

iVinArrow [24]

A) Plan A requires for a percentage increase of a number of students. This means that year after year the number of new students will increase. Plan B requires for a constant number of new students each year. This means that year after year the percentage increase would get smaller.

B) To solve this problem we will use formula for a growth of population:
$final = initial * (1+percentage)^{t}$
Where:
final = final number of students
initial = initial number of students
percentage = requested percentage increase
t = number of years

We can insert numbers and solve for t:
$240= 120* (1+0.12)^{t} \\ 2=1.12^{t} \\ log2=log(1.12^{t} ) \\ log2=t*log1.12 \\ t= \frac{log2}{log1.12} \\ t=6.12years$

For Plan B we can use simple formula
increase = 120
increase per year = 20
number of years = increase / (increase per year) = 120 / 20 = 6 years

Plan B is better to double the <span>enrollment.

C)We use same steps as in B) to solve this.
</span>

$360= 120* (1+0.12)^{t} \\ 3=1.12^{t} \\ log3=log(1.12^{t} ) \\ log3=t*log1.12 \\ t= \frac{log3}{log1.12} \\ t=9.69years$

For Plan B we can use simple formula
increase = 240
increase per year = 20
number of years = increase / (increase per year) = 240 / 20 = 12 years

Plan A is better to triple the enrollment.

3 0

1 year ago