If one is to choose among given choices and the order is not important, we use the concept of combination. First, we calculate for the sample space or number available since there is a total number of 12 electives and a student may choose 2 out of them.
S = 12C2
That is "the sample space is equal to combination of 12 taken 2". The answer to this is equal to 66.
Next, we determine the number of outcomes. The equation will be,
O = (5C1) x (3C1)
That is "outcome is equal to combination of 5 taken 1 times combination of 3 taken 1". This is equal to 15. The probability is equal to,
P = O/S
Substituting,
P = (15/66) = 0.227270
The answer to this item is the third choice.
Answer:
the ablity to choose one is the right now
Step-by-step explanation:
Answer:
20.33%
Step-by-step explanation:
We have that the mean (m) is equal to 87.5, the standard deviation (sd) 6.25 and the sample size (n) = 12
They ask us for P (x <86)
For this, the first thing is to calculate z, which is given by the following equation:
z = (x - m) / (sd / (n ^ 1/2))
We have all these values, replacing we have:
z = (86 - 87.5) / (6.25 / (12 ^ 1/2))
z = -0.83
With the normal distribution table (attached), we have that at that value, the probability is:
P (z <-0.83) = 0.2033
The probability is 20.33%
Answer:
t(d) = 0.01cos(5π(d-0.3)/3)
Step-by-step explanation:
Since we are given the location of a maximum, it is convenient to use a cosine function to model the torque. The horizontal offset of the function will be 0.3 m, and the horizontal scaling will be such that one period is 1.2 m. The amplitude is given as 0.01 Nm.
The general form is ...
torque = amplitude × cos(2π(d -horizontal offset)/(horizontal scale factor))
We note that 2π/1.2 = 5π/3. Filling in the given values, we have ...
t(d) = 0.01·cos(5(d -0.3)/3)
Idk because you did not say yes you did how many sides there were