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2 years ago

If m=8, how many solutions are there for the expression m-8?

Mathematics

1 answer:

ss7ja [257]2 years ago

5 0

Answer:

1 solution, 0

Step-by-step explanation:

In algebra, a variable can be equal to any amount of numbers depending on how it is used. In this case, m is only equal to the one value of 8, and therefore only has one solution.

m - 8

(8) - 8

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Micah is buying items for a birthday party. If he wants to have the same amount of each item, what is the least number of packag

Zolol [24]

For us to be able to answer this question the number of the items that Micah is buying.
....and any important information concerning this problem.

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1 year ago

Read 2 more answers

The Bui family consists of 2 adults and 3 children. They spent $36 for zoo tickets. The equation 2x + 3y = 36 describes the cost

Advocard [28]

Answer:

1) y=12 and 2) (0,12) and (18,0)

Step-by-step explanation:

1) y intercept is when x=0, so 3y=36, y=12

2) the equation of line is y=-(2/3)x+18, so the answer is (0,12) and (18,0)

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1 year ago

You are testing the claim that the mean GPA of night students is different from the mean GPA of day students. You sample 30 nigh

lorasvet [3.4K]

Answer:

Step-by-step explanation:

This is a test of 2 independent groups. The population standard deviations are not known. Let μ1 be the mean GPA of night students and μ2 be the mean GPA of day students.

The random variable is μ1 - μ2 = difference in the mean GPA of night students and the mean GPA of day students.

We would set up the hypothesis.

The null hypothesis is

H0 : μ1 = μ2 H0 : μ1 - μ2 = 0

The alternative hypothesis is

H1 : μ1 ≠ μ2 H1 : μ1 - μ2 ≠ 0

Since sample standard deviation is known, we would determine the test statistic by using the t test. The formula is

(x1 - x2)/√(s1²/n1 + s2²/n2)

From the information given,

x1 = 2.35

x2 = 2.58

s1 = 0.46

s2 = 0.47

n1 = 30

n2 = 25

t = (2.35 - 2.58)/√(0.46²/30 + 0.47²/25)

t = - 1.82

The formula for determining the degree of freedom is

df = [s1²/n1 + s2²/n2]²/(1/n1 - 1)(s1²/n1)² + (1/n2 - 1)(s2²/n2)²

df = [0.46²/30 + 0.47²/25]²/[(1/30 - 1)(0.46²/30)² + (1/25 - 1)(0.47²/25)²] = 0.00025247091/0.00000496862

df = 51

We would determine the probability value from the t test calculator. It becomes

p value = 0.075

Alpha = 5% = 0.05

Since alpha, 0.05 < than the p value, 0.075, then we would fail to reject the null hypothesis.

4 0

2 years ago

If cos(t) = 2/7 and t is in the 4th quadrant, find sin(t).

Yuliya22 [10]

We can use the Pythagorean Trigonometric Identity which says:
$sin^2(t)+cos^2(t)=1$

Since we need to find sin(t), we have to solve for it:
$sin(t)= \sqrt{1-cos^2(t)}$

Let's plug in the given cos(t) value:
$sin(t) = \sqrt{1-cos^2( \frac{2}{7})}$

And solve sin(t):
$sin(t) = \sqrt{1- \frac{4}{49} } = \frac{x}{y} \sqrt{ \frac{49}{49}- \frac{4}{49} }$

Simplify further:
$sin(t) = \sqrt{ \frac{45}{49} } = \frac{ \sqrt{45} }{7} = \frac{ \sqrt{9*5} }{7}$

And it all simplifies down to:
$sin(t) = \frac{3 \sqrt{5} }{7}$

Since it's in the 4th quadrant, the sin(t) value is going to be negative. So, your final answer is:
$sin(t) = - \frac{ 3\sqrt{5} }{7}$

Hope this helps!

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2 years ago

What is the proof the formula for cos(A+B)=cosAcosB-sinAsinB?

brilliants [131]

Given data, cos(A - B) = cosAcosB + sinAsinB
let, A=60' and B=30' ( here the ' sign bears degree) 
L.H.S = cos(A - B) 
=cos (60'-30) ( using value of A and B ) 
=cos30' 
= sqrt3/2 
R.H.S= cosAcosB + sinAsinB 
=cos60' cos30' + sin60' sin30' 
= 1/2* sqrt3/2+ sqrt3/2*1/2 
= sqrt3/4 + sqrt3/4 
=2 sqrt3/4 
= sqrt3/2 
so L.H.S =R.H.S or cos(A - B) = cosAcosB + sinAsinB

8 0

2 years ago