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puteri [66]
2 years ago
7

What is the proof the formula for cos(A+B)=cosAcosB-sinAsinB?

Mathematics
1 answer:
brilliants [131]2 years ago
8 0
Given data, cos(A - B) = cosAcosB + sinAsinB 
<span>let, A=60' and B=30' ( here the ' sign bears degree) </span>
<span>L.H.S = cos(A - B) </span>
<span>=cos (60'-30) ( using value of A and B ) </span>
<span>=cos30' </span>
<span>= sqrt3/2 </span>
<span>R.H.S= cosAcosB + sinAsinB </span>
<span>=cos60' cos30' + sin60' sin30' </span>
<span>= 1/2* sqrt3/2+ sqrt3/2*1/2 </span>
<span>= sqrt3/4 + sqrt3/4 </span>
<span>=2 sqrt3/4 </span>
<span>= sqrt3/2 </span>
<span>so L.H.S =R.H.S or cos(A - B) = cosAcosB + sinAsinB</span>
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Answer:

Step-by-step explanation:

1. regroup terms

125x^3+343+525x^2+735x

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(5x)^3+7^3+525x^2+735x

3. Since both terms are perfect cubes, factor using the sum of cubes formula, a^3+b^3 = (a+b)(a^2-ab+b^2), where a=5x and b=7

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