Answer:
the expected value of Xn , E(Xn) = 0 and the variance σ²(Xn) = n*(1-2n)
Step-by-step explanation:
If X1= number of tails when n fair coins are flipped , then X1 follows a binomial distribution with E(X1) = n*p , p=0,5 and the number of heads obtained is X2=n-X1
therefore
Xn =X1-X2 = X1- (n-X1) = 2X1-n
thus
E(Xn) =∑ (2*X1-n) p(X1) = 2*∑[X1 p(X1)] -n∑p(X1) = 2*E(X1)-n = 2*n*p--n= 2*n*1/2 -n = n-n =0
the variance will be
σ²(Xn) = ∑ [Xn - E(Xn)]² p(Xn) = ∑ [(2X1-n) - 0 ]² p(X1) = ∑ (4*X1²-4*X1*n+n²) p(X1) = = 4*∑ X1²p(X1) - 4n ∑X1 p(X1) - n²∑p(X1) = 2*E(X1²) -4n*E(X1)- n²
since
σ²(X1) = n*p*(1-p) = n*0,5*0,5=n/4
and
σ²(X1) = E(X1²) - [E(X1)]²
n/4 = E(X1²) - (n/2)²
E(X1²) = n(n+1)/4
therefore
σ²(Xn) = 4*E(X1²) -4n*E(X1)- n² = 4*n(n+1)/4 - 4*n*n/2 - n² = n(n+1) - 2n² - n²
= n - 2n² = n(1-2n)
σ²(Xn) = n(1-2n)
The number of people being served went from 6 to 24, so the serving quadrupled.
So multiply 2.5 by 4 and you get 10 pounds of apples.
Answer:
number of cards in a house hold and number of siblings
Step-by-step explanation:
Answer:
ΔVZX and ΔWXZ are not congruent by SAS by the given information.
No, there is not enough information given.
The additional information for triangle to be congruent by SAS is given below.
Step-by-step explanation:
GIVEN:
1. VX = WZ = 40 cm and
2.m∠ZVX = m∠XWZ = 22°
3. VZ = WX ......{this additional information is required for triangles is to be congruent by SAS test}
Proof:
In Δ VZX and Δ WXZ
VZ ≅ WX …………..{additional information}
∠ ZVX ≅ ∠ XWZ ……….{measure of each angle is 22° given}
VX ≅ WZ ………….{length of each side is 40 cm given}
Δ ABC ≅ Δ PQR ….{By Side-Angle-Side test}
For SAS test, two sides of the corresponding triangles should be congruent and the angle between the two side. Then the triangles are said to be congruent by side angle side test.
Answer:
0.15(5,-1)
Step-by-step explanation:
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