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olga nikolaevna [1]

2 years ago

9

) We throw 9 identical balls into 7 bins. How many different ways are there to distribute these 9 balls among the 7 bins such th

at no bin is empty? Assume the bins are distinguishable (e.g., numbered 1 through 7).

1 answer:

ArbitrLikvidat [17]2 years ago

3 0

Answer:

28 ways

Step-by-step explanation:

After placing 1 ball in each of the seven bins, there are two balls left.

If we place both balls in a single bin, there are 7 different ways to place the balls (place both on bins 1 through 7).

If we place each of the remaining balls in a different bin, the number of ways to place the balls is:

$n_2=\frac{7!}{(7-2)!2!}=7*3=21$

The total number of ways to distribute those balls is 21 + 7 = 28 ways.

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The radius of a cylindrical construction pipe is 1.5ft . If the pipe is 14ft long, what is its volume? Use the value 3.14 for π

Lady bird [3.3K]

Answer:

Volume of cylinder =989 ft cube

Step-by-step explanation:

<u>Volume of cylinder</u>

Volume V = πr²h

r - radius and h - height

It is given that,

The radius of a cylindrical construction pipe is 1.5ft and

Length of pipe = 14 ft

<u>To find volume of cylinder</u>

Volume V = πr²h

V = 3.14 x 1.5 x1.5 x 14 =989.1 ≈ 989 ft cube

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1 year ago

You and two friends visit a pizza shop. There are 15 toppings. 5 toppings are meat and the rest are vegetable. Each of you order

viktelen [127]

Chance of u choosing meat is 5/15
first friend chooses, probability is 4/14
second friend chooses, probability is 3/13
so multiplying all 3 probablilities we get 2.2 percent

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1 year ago

The angle measurements in the diagram are represented by the following expressions

Klio2033 [76]

8x-10=3x+90
5x=100
X=20
B=3(20)+90=150

5 0

1 year ago

Read 2 more answers

4. Hydrocarbons in the cab of an automobile were measured during trips on the New Jersey Turnpike and trips through the Lincoln

pochemuha

Answer:

No these these result do not differ at 95% confidence level

Step-by-step explanation:

From the question we are told that

The first concentrations is $c _1= 30.0 \ g/m^3$

The second concentrations is $c _2 = 52.9 \ g/m^3$

The first sample size is $n_1 = 32$

The second sample size is $n_2 = 32$

The first standard deviation is $\sigma_1 = 30.0$

The first standard deviation is $\sigma_1 = 29.0$

The mean for Turnpike is $\= x _1 = \frac{c_1}{n} = \frac{31.4}{32} = 0.98125$

The mean for Tunnel is $\= x _2 = \frac{c_2}{n} = \frac{52.9}{32} = 1.6531$

The null hypothesis is $H_o : \mu _1 - \mu_2 = 0$

The alternative hypothesis is $H_a : \mu _1 - \mu_2 \ne 0$

Generally the test statistics is mathematically represented as

$t = \frac{\= x_1 - \= x_2}{ \sqrt{\frac{\sigma_1^2}{n_1} +\frac{\sigma_2^2}{n_2} }}$

$t = \frac{0.98125 - 1.6531}{ \sqrt{\frac{30^2}{32} +\frac{29^2}{32} }}$

$t = - 0.0899$

Generally the degree of freedom is mathematically represented as

$df = 32+ 32 - 2$

$df = 62$

The significance $\alpha$ is evaluated as

$\alpha = (C - 100 )\%$

=> $\alpha = (95 - 100 )\%$

=> $\alpha =0.05$

The critical value is evaluated as

$t_c = 2 * t_{0.05 , 62}$

From the student t- distribution table

$t_{0.05, 62} = 1.67$

So

$t_c = 2 * 1.67$

=> $t_c = 3.34$

given that

$t_c > t$ we fail to reject the null hypothesis so this mean that the result do not differ

6 0

1 year ago

If a cow has a mass of 9×102 kilograms, and a blue whale has a mass of 1.8×105 kilograms, which of these statements is true?

lana66690 [7]

Answer:

The mass of the Blue whale is 200 times the mass of the cow

Step-by-step explanation:

Given

Mass of Cow = 9 * 10² kg

Mass of Blue Whale = 1.8 * 10⁵ kg

Required

Determine the relationship between both weights

Represent the mass of the cow with C and the mass of the whale with B

$C = 9 * 10^2kg$

$C = 9 *100kg$

$C = 900kg$

$B = 1.8 * 10^5kg$

$B = 1.8 * 100000kg$

$B = 180000kg$

Divide the bigger weight by the smaller weight

$\frac{B}{C} = \frac{180000kg}{900kg}$

$\frac{B}{C} = \frac{180000}{900}$

$\frac{B}{C} = {200}{}$

Multiply both sides by C

$C * \frac{B}{C} = {200}{} * C$

$B = {200}{} * C$

$B = 200}C$

<em>From the expression above, it can be concluded that the mass of the Blue whale is 200 times the mass of the cow</em>

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1 year ago