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olga nikolaevna [1]
2 years ago
9

) We throw 9 identical balls into 7 bins. How many different ways are there to distribute these 9 balls among the 7 bins such th

at no bin is empty? Assume the bins are distinguishable (e.g., numbered 1 through 7).
Mathematics
1 answer:
ArbitrLikvidat [17]2 years ago
3 0

Answer:

28 ways

Step-by-step explanation:

After placing 1 ball in each of the seven bins, there are two balls left.

If we place both balls in a single bin, there are 7 different ways to place the balls (place both on bins 1 through 7).

If we place each of the remaining balls in a different bin, the number of ways to place the balls is:

n_2=\frac{7!}{(7-2)!2!}=7*3=21

The total number of ways to distribute those balls is 21 + 7 = 28 ways.

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The fraction of squares shaded to total squares is 70/100  or 7/10
With a percent, 70% of all of the squares are shaded
With a decimal, there are 0.7 shaded blocks for every total block, so it is 0.7
Hope this helps!
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"Consider the probability distribution of X, where X is the number of job applications completed by a college senior through the
Citrus2011 [14]

Answer:

Option b

Step-by-step explanation:

Given that the probability distribution of X, where X is the number of job applications completed by a college senior through the school’s career center.

 Expected observed Diff

x p(x) p(x)*1000  

   

0 0.002 2  

1 0.011 11 14 -3

2 0.115 115 15 100

3 0.123 123 130 -7

4 0.144 144  

5 0.189 189  

6 0.238 238  

7 0.178 178  

   

1 1000

We find that there is a large difference in 2 job application

Hence option b is right.  

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2 years ago
On a coordinate plane, a line with a 90-degree angle crosses the x-axis at (negative 4, 0), turns at (negative 1, 3), crosses th
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b

Step-by-step explanation:

3 0
2 years ago
Conservation of Species A certain species of turtle faces extinction because dealers collect truckloads of turtle eggs to be sol
JulijaS [17]

Answer:

The turtle population's rate of growth will be 32 turtles per year after 2 years and 248 per year after 6 years.

Ten years after the conservation measures are implemented the population will be 3260 turtles.

Step-by-step explanation:

To find the rate of growth of the turtle population at any time <em>t</em> you need to find N'(t)

\frac{d}{dt}N(t)=\frac{d}{dt}(2t^3+3t^2-4t+1000)\\\\\mathrm{Apply\:the\:Sum/Difference\:Rule}:\quad \left(f\pm g\right)'=f\:'\pm g'\\\\\frac{d}{dt}(2t^3)+\frac{d}{dt}(3t^2)-\frac{d}{dt}(4t)+\frac{d}{dt}(1000)\\\\\mathrm{Apply\:the\:Power\:Rule}:\quad \frac{d}{dx}\left(x^a\right)=a\cdot x^{a-1}\\\\N'(t)=6t^2+6t-4

In particular, when t = 2 and t = 6, we have

N'(2)=6(2)^2+6(2)-4=32\\\\N'(6)=6(6)^2+6(6)-4=248

so the turtle population's rate of growth will be 32 turtles per year after 2 years and 248 per year after 6 years.

The turtle population at the end of the tenth year will be

N(10)=2(10)^3+3(10)^2-4(10)+1000\\N(10)=3260 \:turtles

3 0
2 years ago
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