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Trava [24]
2 years ago
6

Makayla is working two summer jobs, making $19 per hour tutoring and making $12 per hour landscaping. In a given week, she can w

ork no more than 17 total hours and must earn at least $260. If Makayla worked 3 hours landscaping, determine the minimum number of whole hours tutoring that she must work to meet her requirements. If there are no possible solutions, submit an empty answer.
Mathematics
1 answer:
Ivanshal [37]2 years ago
8 0

Answer: 12 hours

Step-by-step explanation:

3 hours landscaping = $36

She still needs to make $224 to meet her requirement.

$224 divided by $19 tutoring = 11.79 hours

224÷19=11.79

Rounded to the nearest whole number: 12

This would mean Makayla worked a total of 15 hours and made $264. Which meets her requirements.

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Whats another way to write 300 70 5/10 8/100?
Aloiza [94]
I don't understand what you mean by 300 and 70, unless you meant 300/70 (in that case it would be 30/7). 


5/10 would be 1/5


8/100 would be 2/25.
8 0
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Noah planned a parallelogram-shaped sidewalk to lead from the street to the front door of his house. He realized the walkway was
nekit [7.7K]

Answer:

Step-by-step explanation:

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If f(x) = 5x + 40, what is f(x) when x = –5?<br><br> a.–9<br> b.–8<br> c.7<br> d.15
defon

Just plug the number

_5(5)+40=-25+40

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2 years ago
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In the transmission of digital information, the probability that a bit has high, moderate, and low distortion is 0.02, 0.07, and
Leviafan [203]

Answer:

A. (Table Attached)

B. (See Step 3)

C. 0.06 (See Step 4)

D. NOT independent (See Step 5)

Step-by-step explanation:

<h3 /><h3>STEP 1:</h3>

Name the probabilities:

p₁ = 0.02,   p₂ = 0.07,   p₃ = 0.91

q₁ = 1-p₁ = 0.98 ,   q₂ = 1-p₂ = 0.93 ,   q₃ = 0.09

Let X and Y be the number of bits with high and moderate distortion out of three.

<h3>STEP 2:</h3>

A.

The function will follow multinomial distribution:

f_{XY}(x,y) = P(X=x, Y=y) = \frac{3!}{x!y!(3-x-y)!} (p_1^x)(p_2^y)(p_3^{3-x-y})

Substitute the values and make a table.

TABLE IN ATTACHMENT

<h3>STEP 3:</h3>

B.

We calculate marginal distribution by:

P (X=x)= <em>∑</em> P(X=x,Y=y)

fx(x) can be found by adding all the probabilities in each row for different value of X

For X=0 , ∑P = 0.94157441

For X=1 , ∑P = 0.057624

For X=2 , ∑P = 0.001176

For X=3 , ∑P =0.000008

<h3>STEP 4:</h3><h3>C.</h3>

The mathematic expectation E is the sum of product of each possibility with its probabiity.

E(X)=<em>∑ </em>xP(X=x)

Find E(X):

E(X)= (0*0.9415744)+(1*0.057624)+(2*0.001176)+(3*0.000008)

E(X)=0.06

<h3>STEP 5:</h3>

Condition probability states:

P(A|B)=\frac{P(A,B)}{P(B)}

It can also be written as:

f_{Y|X=1}(y)=\frac{f_{XY}(1,y)}{f_x(1)}

Where f_x(1)\\ = 0.057624

Calculate the quotient:

Y|_{x=1} = 0 ,  f_{Y|_X=1 = 0.862245

Y|_{x=1} = 1 ,  f_{Y|_X=1 = 0.132653

Y|_{x=1} = 2 ,  f_{Y|_X=1 = 0.000510

Y|_{x=1} = 3 ,  f_{Y|_X=1 = 0

Find the dependency:

f_{XY}(y)=f_X(x)f_Y(y)

We found that

f_{Y|_X=1 = 0.862245

Calculate f_Y(1) from summing the column from the table

f_Y(1)=0.17428341+0.007644+0.000084\\f_Y(1)=0.18201141

Which are not equal.

Conclusion:

X and Y are NOT Independent

7 0
2 years ago
the table shows the number of minutes Tim has for lunch and study hall. he calculates that these two periods account for 18% of
EleoNora [17]

Tim spends 500 minutes at the school.

Step-by-step explanation:

Given,

Time for lunch = 45 minutes

Time for study hall = 45 minutes

Total = 45+45 = 90 minutes

This represents 18% of the total minutes Tim spend at school.

Let,

x be the total minutes Tim spend at school.

18% of x = 90 minutes

\frac{18}{100}x=90\\\\0.18x=90

Dividing both sides by 0.18

\frac{0.18x}{0.18}=\frac{90}{0.18}\\x=500

Tim spends 500 minutes at the school.

Keywords: percentage, division

Learn more about division at:

  • brainly.com/question/101683
  • brainly.com/question/103144

#LearnwithBrainly

5 0
2 years ago
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