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1 year ago

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A random survey of seventh and eighth grade students was conducted to find out how many hours are spent doing homework each nigh

t. Of the two sets of data, which has the greater median?
A: seventh graders
B: eighth graders
C: they have the same median
D: impossible to determine from the box plot

1 answer:

sammy [17]1 year ago

4 0

Eight graders is the answer

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JL has coordinates J(-6, 1) and L(-4,3).<br> Find the coordinates of the midpoint.

ikadub [295]

Answer:

The coordinates of the mid-point of JL are (-5 , 2)

Step-by-step explanation:

If point (x , y) is the mid-point of a segment whose end-points are $(x_{1},y_{1})$ and $(x_{2},y_{2})$ , then $x=\frac{x_{1}+x_{2}}{2}$ and $y=\frac{y_{1}+y_{2}}{2}$

∵ JL is a segment

∵ The coordinates of J are (-6 , 1)

∴ $x_{1}$ = -6 and $y_{1}$ = 1

∵ The coordinates of L are (-4 , 3)

∴ $x_{2}$ = -4 and $y_{2}$ = 3

Lets use the rule above to find the mid-point of JL

∵ $x=\frac{-6+-4}{2}=\frac{-10}{2}$

∴ x = -5

∴ The x-coordinate of the mid-point is -5

∵ $y=\frac{1+3}{2}=\frac{4}{2}$

∴ y = 2

∴ The y-coordinate of the mid-point is 2

∴ The coordinates of the mid-point of JL are (-5 , 2)

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2 years ago

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galina1969 [7]

So, we would need to remember, the one way that me personally would view square rooting would be by simplifying them, and that number would go into that number that many times. So, when doing this kind of problem, we are not truly going to do this, but we are just going to simplify it, and to see what other square "rooter" would go into that.

So, we would need to remember a (key) point, <em>we aren't just multiplying, for the most part, we're simplifying. </em>

Our result:

$\boxed{\boxed{\bf{2a^2b \sqrt[4]{24a^2b^3} }}}$

We didn't just multiplied it, we also simplified it also.

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1 year ago

Quadrilateral CAMP below is a rhombus. the length PQ is (x+2) units, and the length of QA is (3x-14) units. Which statements bes

valentinak56 [21]

Answer:

<h3>Q cuts the diagonal PA into 2 equal halves, since the diagonals of rhombus meet at right angles.</h3><h3>The value of x is 8.</h3>

Step-by-step explanation:

Given that Quadrilateral CAMP below is a rhombus. the length PQ is (x+2) units, and the length of QA is (3x-14) units

From the given Q is the middle point, which cut the diagonal PA into 2 equal halves.

By the definition of rhombus, diagonals meet at right angles.

Implies that PQ = QA

x+2 = 3x - 14

x-3x=-14-2

-2x=-16

2x = 16

dividing by 2 on both sides, we will get,

$x =\frac{16}{2}$

<h3>∴ x=8</h3><h3>Since Q cuts the diagonal PA into 2 equal halves, since the diagonals of rhombus meet at right angles we can equate x+2 = 3x-14 to find the value of x.</h3>

The line segment $\overrightarrow{PA}=\overrightarrow{PQ}+\overrightarrow{QA}$

$\overrightarrow{PA}=x+2+3x-14$

$=4x-12$

$=4(8)-12$ ( since x=8)

$=32-12$

$=20$

<h3>∴ $\overrightarrow{PA}=20$ units</h3>

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2 years ago

3 lines are shown. A line with points M, H, K intersects with a line with points J, H, L at point H. Another line extends from p

otez555 [7]

Answer:

Option B.

Step-by-step explanation:

Given information: ∠MHL=(3x+20), ∠KHN=(x+25), and ∠JHN=(x+20).

We need to find the measure of ∠JHN.

$\angle MHL=\angle JHK$ (Vertical opposite angles)

$\angle MHL=\angle JHN+\angle KHN$

Substitute the given values.

$3x+20=(x+20)+(x+25)$

$3x+20=2x+45$

$3x-2x=45-20$

$x=25$

The value of x is 25. So, the measure of ∠JHN is

$\angle JHN=x+20=25+20=45$

The measure of ∠JHN is 45°.

Therefore, the correct option is B.

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Alenkinab [10]

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1 year ago

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