Answer:
Accuracy = 0.81
Sensitivity = 0.93
Specificity = 0.81
Precision = 0.047
Step-by-step explanation:
Given the confusion matrix :
Actual_______ Donation___ No Donation
Donation______ 268 (TP) _______ 20 (FN)
No Donation ___5375 (FP) _____23439 (TN)
Accuracy is calculated as :
(TP + TN) / (TP+TN+FP+FN)
(268 + 23439) / (268 + 23439 + 5375 + 20)
ACCURACY = (23707 / 29102) = 0.81
Sensitivity (True positive rate) :
TP ÷ (TP + FN)
268 ÷ (268 + 20)
268 ÷ 288 = 0.93
Specificity (True Negative rate) :
TN ÷ (TN + FP)
23439 ÷ (23439 + 5375)
23439 ÷ 28814
= 0.81
Precision :
TP ÷ (TP + FP)
268 ÷ (268 + 5375)
268 ÷ 5643
= 0.047
The best way to randomly choose the 100 families would be to allow a random number generator to come up with 100 families within a 50 radius of the amusement park.
Using this method would ensure that it is more randomised & not limited to people who come at a specific time or are in a specific area as well as it not be affected by subconscious bias of people when selecting people to survey.
Answer:
x = $3, or x = $11
Step-by-step explanation:
The equation given is
where
- P(x) is the profit, and
- x is the app price
<u>We want app prices (x's) when profit (P(x)) is 0, so plugging in into the equation:</u>

<em>It means (x-3) = 0 OR (x-11) = 0</em>
So, x = 3, or 11
See attached image
First, we must know this: Complementary angles are two angles whose sum is equal to 90°, while supplementary angles are two angles whose sum is equal to 180°. That been said, the only statement which is true is the second statement, <span>
MNL is complementary to KNL
Reasons why others are False</span>GNJ is supplementary to JNK, not complementary
MNG is supplementary to GNJ, not complementary
LNJ (not KNJ) <span>is supplementary to MNL
</span>GNM is equal to JNK, not supplementary
Answer:
Yes, it would be statistically significant
Step-by-step explanation:
The information given are;
The percentage of jawbreakers it produces that weigh more than 0.4 ounces = 60%
Number of jawbreakers in the sample, n = 800
The mean proportion of jawbreakers that weigh more than 0.4 = 60% = 0.6 =
=p
The formula for the standard deviation of a proportion is 
Solving for the standard deviation gives;

Given that the mean proportion is 0.6, the expected value of jawbreakers that weigh more than 0.4 in the sample of 800 = 800*0.6 = 480
For statistical significance the difference from the mean = 2×
= 2*0.0173 = 0.0346 the equivalent number of Jaw breakers = 800*0.0346 = 27.7
The z-score of 494 jawbreakers is given as follows;


Therefore, the z-score more than 2 ×
which is significant.