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RSB [31]
2 years ago
11

ants have 6 legs. Elena and Andre write equations showing the proportional relationship between the number of ant legs L Elena w

rites a=6 X L and Andre write L=0.166666666667 X a.do you agree with either of the Equations?explain your reasoning
Mathematics
2 answers:
barxatty [35]2 years ago
7 0

Answer:

Neither are correct.

Step-by-step explanation:

The number of legs = the number of ants * 6.

The relationship is L = 6 a   so neither are correct.

ludmilkaskok [199]2 years ago
7 0

Answer: Both equations are incorrect.

Step-by-step explanation:

Ants have 6 legs:

The equation of Elena is:

a = 6*L

where a is ants and L is legs.

this equation says that are equal number of ants tan 6 times the number of legs, this is is not the case;

the number of legs is six times the number of ants, because each ant has 6 legs: L =6*a

the Andre equation is:

L = 0.166*a

Which, again, it is incorrect.

in this case the equation should be:

a = 0.166*L

and the ratio of ants to legs is 1:6 wich means that there is one ant for each 6 legs.

Both options are incorrect

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Cassie has 20 bracelets. How many can she give to her sister if she wants to keep 11 or more bracelets? What repeats in the poss
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Harrison Water Sports has two retail outlets: Seattle and Portland. The Seattle store does 60 percent of the total sales in a ye
Anna11 [10]

Answer: P = 0.75

Step-by-step explanation:

Hi!

The sample space of this problems is the set of all the possible sales. It is divided in the disjoint sets:

S_s = {\text{sales made in Seattle }}\\S_p={\text {sales made in Portland}}

We have also the set of sales of boat accesories S_b, the colored one in the image.

We are given the data:

P(S_s) = 0.6\\P(S_b | S_s) = \frac{P(S_b\bigcap S_s)}{P(S_s)}=0.4\\P(S_b|S_p) =\frac{P(S_b\bigcap S_p)}{P(S_p)}=0.2

From these relations you can compute the probabilities of the intersections colored in the image:

pink\;set:\;P(S_b \bigcap S_s) =0.6*0.4=0.24\\blue\;set\;:P(S_b \bigcap S_p)=(1-0.6)*0.2 =0.08

You are asked about the conditional probability:

P(S_s|S_b) = \frac{P(S_s \bigcap S_b)}{P(S_b)}

To calculate this, you need  P(S_b) . In the image you can see that the set S_b is the union of the two disjoint pink and blue sets. Then:

P(S_b)=P((S_b \bigcap S_s)\bigcup(S_b \bigcap S_p)) = 0.24 + 0.08 = 0.32

Finally:

P(S_s|S_b) = \frac{0.24}{0.32}=0.75

4 0
2 years ago
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