Lines a and b are cut by transversal f. At the intersection of lines f and a, the top left angle is 96 degrees. At the intersect
ion of lines b and f, the bottom right angle is (6 x minus 36) degrees.
What must be the value of x so that lines a and b are parallel lines cut by transversal f?
10
20
22
32
What must be the value of x so that lines a and b are parallel lines cut by transversal f?
10
20
22
32
2 answers:
Answer:
Option C.
Step-by-step explanation:
It is given that lines a and b are cut by transversal f.
If a transversal line intersect two parallel lines, then the alternate exterior angles are same.
We need to find the value of x so that lines a and b are parallel lines cut by transversal f.
So, equate both alternate exterior angles.
Add 36 on both sides.
Divide both sides by 6.
The value of x is 22. Therefore, the correct option is C.
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They will have to bring in more than $600,000 a month to beat their competitors.
Step-by-step explanation:
Step 1; This establishment's competitors bring in $1,800,000 per quarter. This means that they bring in that amount of money through sales in a quarter of a year.
A quarter of a year = × 12 months = 3 months.
So the competition brings in $1,800,000 in 3 months.
Step 2; Now we calculate how much this establishment must make to beat them.
Money to brought in a month = $1,800,000 / 3= $600,000 a month. So the team must bring in more than $600,000 a month to beat their competitor's sales of $1,800,000 in a quarter.