For this case we have the following complex number:
1 + i
Its equivalent pair is given by:
root (2) * (cos (pi / 4) + i * sin (pi / 4))
Rewriting we have:
root (2) * (root (2) / 2 + i * (root (2) / 2))
(2/2 + i * (2/2))
(1 + i)
Answer:
option A represents a pair with the same complex number
Answer:
<h2>The domain is all real values of x except

.</h2>
Step-by-step explanation:
The function,
.
g(x) = 5x - 4.
Hence, (f circle g) (x) =
.
We need to find the domain of (f circle g) (x) .
The domain means the set of values of x, for which we will get a real value of (f circle g) (x).
The function will not give a real value when, 5x - 4 = 0 that is
.
Hence, the domain of the function will be all real values of x rather than
.
To find the specification limit such that only 0.5% of the bulbs will not exceed this limit we proceed as follows;
From the z-table, a z-score of -2.57 cuts off 0.005 in the left tail; given the formula for z-score
(x-μ)/σ
we shall have:
(x-5000)/50=-2.57
solving for x we get:
x-5000=-128.5
x=-128.5+5000
x=4871.50
Answer:
Step-by-step explanation:
Ive already explained this somebody else asked if you find it you will have the answer
Let the variable of the equation be x.
I'm gonna go backwards of the factorization process.
Given,
x = 11 or 3
(x - 11)(x - 3) = 0
x² -3x -11x + 33 = 0
x² -14x + 33 = 0
Hence, f(x) = x² - 14x + 33.