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shusha [124]
2 years ago
9

A hotel has 12 floors and 2,220 rooms. There are the same number of rooms on each floor of the hotel.

Mathematics
2 answers:
oee [108]2 years ago
8 0
Just simply divide 2,220 by 12 and you’ll get 185 rooms on each floor.
Naddik [55]2 years ago
5 0
185 on each floor

2220/12
You might be interested in
It is 1 1/4 miles from Ahmed’s house to school. How far does Ahmed’s travel in 5 days walking to school and back
Sauron [17]

Ahmed travel 12\frac{1}{2} miles in 5 days walking to school and back.

Step-by-step explanation:

Distance from house to school = 1\frac{1}{4} miles

Distance from school to house = 1\frac{1}{4} miles

Total distance in 1 day = 1\frac{1}{4}+1\frac{1}{4}=\frac{5}{4}+\frac{5}{4}

Total distance in 1 day = \frac{5+5}{4}=\frac{10}{4}

Distance traveled in 5 days = 5*\frac{10}{4}=\frac{50}{4}

Distance traveled in 5 days = \frac{25}{2}=12\frac{1}{2}

Ahmed travel 12\frac{1}{2} miles in 5 days walking to school and back.

Keywords: fraction, addition

Learn more about fractions at:

  • brainly.com/question/10435816
  • brainly.com/question/10435836

#LearnwithBrainly

5 0
2 years ago
A scientist had a bottle that contains 56.6 ML of a solution. she used 3.2 ML of the solution for an experiment then she poured
hjlf
1. 56.6 - 3.2 = 53.4
2. 53.4 divided by 2 = 26.7
3. 26.7 - 6 = 20.7
Answer: 20.7 mL
3 0
2 years ago
Find the dimensions of the box with volume 1728 cm3 that has minimal surface area. (Let x, y, and z be the dimensions of the box
Gala2k [10]

Answer:

The dimensions of the box are 12 cm , 12 cm , 12 cm

Step-by-step explanation:

Let x , y and z be the dimensions of box

Volume of box =xyz=1728

z=\frac{1728}{xy}

Surface area of box = 2xy+2yz+2xz=2xy+2y(\frac{1728}{xy})+2x(\frac{1728}{xy})

Let f(x,y)=2xy+2(\frac{1728}{x})+2(\frac{1728}{y})

To get minimal surface area

\frac{\partial f}{\partial x}=0 and \frac{\partial f}{\partial y}=0

\frac{\partial(2xy+2(\frac{1728}{x})+2(\frac{1728}{y}))}{\partial x}=0

2y-2(\frac{1728}{x^2})=0

y=\frac{1728}{x^2} ----1

\frac{\partial(2xy+2(\frac{1728}{x})+2(\frac{1728}{y}))}{\partial y}=0

2x-2(\frac{1728}{y^2})=0\\x=\frac{1728}{y^2}  \\y^2=\frac{1728}{x}

Using 1

(\frac{1728}{x^2} )^2=\frac{1728}{x}

x=0 and x^3=1728

Side can never be 0

So,x^3=1728

x=12

y=\frac{1728}{x^2} \\y=\frac{1728}{12^2}

y=12

z=\frac{1728}{xy}\\z=\frac{1728}{(12)(12)}

z=12

The dimensions of the box are 12 cm , 12 cm , 12 cm

5 0
2 years ago
Find the sum of the first 30 terms of the sequence below an=3n+2
Solnce55 [7]
First off, let's find the 1st term's value, and the 30th term's value,

\bf a1=3(1)+2\implies a1=5\qquad \qquad \quad   a30=3(30)+2\implies a30=92\\\\
-------------------------------\\\\
~~~~~~~\textit{ Sum of an arithmetic sequence}\\\\
S_n=\cfrac{n(a1+an)}{2}~ 
\begin{cases}
n=n^{th}\ term\\
a1=\textit{first term's value}\\
----------\\
a1=5\\
a30=92\\
n=30
\end{cases} \implies S_{30}=\cfrac{30(5+92)}{2}
\\\\\\
S_{30}=15(97)
6 0
2 years ago
Read 2 more answers
A production line operates with a mean filling weight of 16 ounces per container. Overfilling or underfilling presents a serious
Dominik [7]

Answer:

Part1) z=\frac{16.32-16}{\frac{0.8}{\sqrt{30}}}=2.191    

p_v =2*P(Z>2.191)=0.0284

Readjustment is needed

Part 2)  z=\frac{15.82-16}{\frac{0.8}{\sqrt{30}}}=-1.232    

z=\frac{15.82-16}{\frac{0.8}{\sqrt{30}}}=-1.232    

p_v =2*P(Z

No readjustment is needed

Step-by-step explanation:

Data given and notation

Part 1    

\bar X=16.32 represent the sample mean    

\sigma=0.8 represent the population standard deviation    

n=30 sample size    

\mu_o =16 represent the value that we want to test    

\alpha=0.05 represent the significance level for the hypothesis test.    

z would represent the statistic (variable of interest)    

p_v represent the p value for the test (variable of interest)    

State the null and alternative hypotheses.    

We need to apply a two tailed test.    

What are H0 and Ha for this study?    

Null hypothesis:  \mu =16    

Alternative hypothesis :\mu \neq 16    

Compute the test statistic  

The statistic for this case is given by:    

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)    

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".    

Calculate the statistic    

We can replace in formula (1) the info given like this:    

z=\frac{16.32-16}{\frac{0.8}{\sqrt{30}}}=2.191    

Give the appropriate conclusion for the test  

Since is a two tailed test the p value would be:    

p_v =2*P(Z>2.191)=0.0284

Using the value of \alpha =0.05 we see that pv and we have enough evidence to reject the null hypothesis.

Readjustment is needed

The rejection zone is given by:

(-\infty ;-1.96) , (1.96;\infty)    

Part 2

\bar X=15.82 represent the sample mean    

We can replace in formula (1) the info given like this:    

z=\frac{15.82-16}{\frac{0.8}{\sqrt{30}}}=-1.232    

Give the appropriate conclusion for the test  

Since is a two tailed test the p value would be:    

p_v =2*P(Z

Using the value of \alpha =0.05 we see that pv>\alpha and we have enough evidence to FAIL to reject the null hypothesis.

No readjustment is needed

The rejection zone is given by:

(-\infty ;-1.96) , (1.96;\infty)  

What action would you recommend ?

Review the procedure.

Do you reach the same conclusion ?

No we got different conclusions

5 0
2 years ago
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