Minute Maid states that a bottle of juice contains 473 mL. Consumer groups are interested in determining if the bottles contain
1 answer:
Answer:
Option C) The average contents of all bottles of juice in the population, which is 473 mL
Step-by-step explanation:
We are given the following in the question:
Population mean, μ = 473 mL
Sample mean, = 472 mL
Sample size, n = 30
Sample standard deviation, σ = 0.2
First, we design the null and the alternate hypothesis
Representation of
is the population parameter that represents the population mean.
Thus, for the given situation represents:
Option C) The average contents of all bottles of juice in the population, which is 473 mL
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Answer:
Null hypothesis be H₀ : μ = 100
Alternative hypothesis Hₐ : μ < 100
There is sufficient statistical evidence to suggest that the average location of Wade Tract is 100
Step-by-step explanation:
Here we have;
Let our null hypothesis be H₀ : μ = 100 Average location of trees in the Wade Tract is 100
Our alternative hypothesis becomes Hₐ : μ < 100 at 95% confidence level
Proposed average location in Wade Tract, μ = 100
Sample mean, = 99.74
Standard deviation, s = 58
Sample size, n = 584
The t test formula is therefore;
Therefore, with df = 584 -1 = 583, and α = (1 - 0.95)/2 = 0.025
We have = -1.65
Plugging in the values into the t test formula, we have t = -0.108338, from which the p-value is given as p = 0.4569 which is much more than the value of α, therefore, we accept the null hypothesis as follows;
There is sufficient statistical evidence to suggest that the average location of Wade Tract = 100.
In the given diagram, line BG bisects ∠ABC and ∠DEF, m∠ABC= 112°, and ∠ABC≅∠DEF. So the measure of angles are :
1. m∠DEF= 112° because ∠ABC≅∠DEF
2. m∠ABG= 56° because a straight line BG is bisecting ∠ABC in two equal parts. So,
3. m∠CBG= 56° because ∠ABG and ∠CBG are equal.
4. m∠DEG= 56° because ∠ABG ≅ ∠DEG
Answer:
If we solve for k we can do this:
So then we have at last 75% of the data withitn two deviations from the mean so the limits are:
Step-by-step explanation:
We don't know the distribution for the scores. But we know the following properties:
For this case we can use the Chebysev theorem who states that "At least of the values lies between
and
"
And we need the boundaries on which we expect at least 75% of the scores. If we use the Chebysev rule we have this:
If we solve for k we can do this:
So then we have at last 75% of the data withitn two deviations from the mean so the limits are: