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nirvana33 [79]
2 years ago
15

Simplify this expression: One-half k squared + g minus 3 + one-half k squared minus 3 + 2 g k2 + 3g – 6 One-fourthk2 + 3g 3g + 9

k2 – 3

Mathematics
2 answers:
Alborosie2 years ago
7 0

Answer:

The answer is A, k2 + 3g – 6

Step-by-step explanation:

did the assignment on edge2020

Anna11 [10]2 years ago
6 0

A:

Simplify this expression:  One-half k squared + g minus 3 + one-half k squared minus 3 + 2 g

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The cafeteria staff made sandwiches. Each sandwich had either rye or white bread, either ham or turkey, and either cheese or no
Anit [1.1K]

Answer:

1/2 (1 half)

Step-by-step explanation:

The number of different sandwiches is calculated multiplying all of the possibilities for each material used:

rye or white bread: 2 options

ham or turkey: 2 options

cheese or no cheese: 2 options

So the number of different sandwiches that can be made is 2*2*2 = 8.

From these 8 different sandwiches, 4 have cheese and 4 have no cheese, as the staff made a equal number of each type of sandwich.

So, if from 8 different type of sandwiches, 4 have cheese, the chances of Mary getting a sandwich with cheese is 4/8 = 1/2 (1 half).

8 0
2 years ago
Find the first, fourth, and eighth terms of the sequence. A(n) = –3 • 2^n–1
Sphinxa [80]
A(n) = –3 • 2⁽ⁿ⁻¹⁾

for n = 1 ,  A₁ = -3.(2)⁰ = -3
for n = 2 ,  A₂ = -3.(2)¹ = -6
for n = 3 ,  A₃ = -3.(2)² = -12
for n = 4 ,  A₄ = -3.(2)³ = -24
...........................................
for n = 8 ,  A₈ = -3.(2)⁷ = -384


4 0
1 year ago
Robby had 4 4/9 bags of pet food.All of the bags held the same amount of food when they were full.Of Robby's 4 4/9 bags of pet f
Tpy6a [65]

Answer: 1.8 bags

Step-by-step explanation:

From the question, given that robby have 4 4/9 bags of pet food, 2/5 were dog food

2/5 of 4 4/9 = dog foods

Convert 4 4/9 to proper fraction= 40/9

2/5 of 40/9 means 2/5 × 40/9

= 16/9

= 1.78 or 1.8

I hope this helps, please mark as brainliest answer.

4 0
2 years ago
PLS HELP, 50 POINTS!!!
Sedaia [141]

Answer:

Part A: From 0 to 2 seconds, the height of the water balloon increases from 60 to 75 feet, therefore the water balloon's height is increasing during the interval [0,2]

Part B: From 2 to 4 seconds, the height of the water balloon stays the same at 75 feet, therefore the water balloon's height is the same during the interval [2,4] From 10 to 12 seconds, the height of the water balloon stays the same at 0 feet, therefore the water balloon's height is the same during the interval [10,12] From 12 to 14 seconds, the height of the water balloon stays the same at 0 feet, therefore the water balloon's height is the same during the interval [12,14] 

Part C: The interval, [4,6] of the domain is when the water ballon's height decreases the fastest. The interval [4,6] decreases by 35 feet. The two other intervals that decrease are [6,8] and [8,10] which both have the same slope. They decrease by 20 feet. Therefore, this helps us conclude that the interval [4,6] decreases the fastest because 35 feet is a more significant decrease than 20 feet. 

Part D: I predict that the height of the water balloon at 16 seconds is 0 feet. This is because at 10-14 seconds, the water balloon's height is 0 feet. In read-world situations, if the water balloon is on the ground which is 0 feet, it stays on the ground due to gravity. 

Step-by-step explanation:

I hope this helps! I also do not know if it is all correct but I did research and everything so hopefully it is correct! Good luck!

8 0
2 years ago
Read 2 more answers
If the instructions for a problem ask you to use the smallest possible domain to completely graph two periods of y = 5 + 3 cos 2
erica [24]
Hello,

y=5+3*cos (2(x-π/3))

The function is periodic with periode=2π.


-1<=cos (2(x-π/3))<=1
==>-1*3<=3*cos (2(x-π/3))<=3*1
==>5-3<=5+3cos(2(x-π/3))<=5+3
==>2<= y<=8


8 0
2 years ago
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