For this case we have that the variable "x" represents the number of hours that Leticia uses to take care of children on Saturday.
IF on Friday I use 4 hours ($ 8 each) and on Saturday "x" hours ($ 8 each) obtaining a profit of $ 72, we have the following equation:
We apply distributive property:
So, on Saturday she spent 5 hours.
Answer:
Answer:
No. The last ratio is not written with the values in the same position as the others. It should be 50
10
to be consistent. If the ratio were written this way, then the ratios would all be equivalent . The relationship is proportional.
Step-by-step explanation:
I just did this!
Hello there! So, let's do this a bit at a time. Mike's Bikes sells a bike for $300, but gives a 25% discount for any bike in the store. To find out how much he would pay for the bike, multiply 300 by 75% (0.75). This is because you are still paying 75% of the original price for that bike. When you do, you get 225. That's $225 for the bike at Mike's Bikes. Now, the one at Cycle Center sells a bike for $275, but gives a rebate of $40 after purchasing the bike. A rebate is basically a refund: you get money paid back to you. In this case, we would subtract 40 from 275, because you're basically getting paid back some of what you did pay. 275 - 40 is 235. That's $235 for the bike at Cycle Center. I'll write the prices of the bikes out to make it easier to read.
Mike's Bikes: $225
Cycle Center: $235
Okay. so when you look at the prices for the mountain bikes, you see that the bike at Mike's Bikes is $10 cheaper than the bike at Cycle Center. Dante should purchase his mountain bike at Mike's Bikes, because he will pay less money there. The Cycle Center does give $40 back, but Mike's Bikes has the bike that costs less. 225 < 235.
(x) = arcsec(x) − 8x
f'(x) = d/dx( arcsec(x) −
8x )
<span> 1/xsqrt( x^2 - 1) - 8</span>
f'(x) = 0
1/xsqrt( x^2 - 1) - 8 = 0
8 x sqrt (x^2-1) = 1
<span> ( 8 x sqrt (x^2-1) )^2 = 1</span>
64 x^2 ( x^2 - 1) = 1
64 x^4 - 64 x^2 =1
64 x^4 - 64 x^2 - 1 = 0
x = 1.00766 , - 1.00766
<span> x = - 1.00766</span>
f(- 1.00766) = arcsec(-
1.00766) − 8( - 1.00766)
f( - 1.00766 ) = 11.07949
x = 1.00766
f(1.00766) =
arcsec(1.00766) − 8( 1.00766)
f(1.00766 ) = -7.93790
relative maximum (x, y) =
(- 1.00766 , 11.07949 ) relative minimum (x, y) = ( 1.00766 ,
-7.93790 )
<span>D=20+50t
120=20+50t
50t=100
t=2 hours
Domain of t from t=-(2/5)hr to t=2hr. Since they already drove 20 miles.
[-2/5,2]</span>
