Answer:
y2 = C1xe^(4x)
Step-by-step explanation:
Given that y1 = e^(4x) is a solution to the differential equation
y'' - 8y' + 16y = 0
We want to find the second solution y2 of the equation using the method of reduction of order.
Let
y2 = uy1
Because y2 is a solution to the differential equation, it satisfies
y2'' - 8y2' + 16y2 = 0
y2 = ue^(4x)
y2' = u'e^(4x) + 4ue^(4x)
y2'' = u''e^(4x) + 4u'e^(4x) + 4u'e^(4x) + 16ue^(4x)
= u''e^(4x) + 8u'e^(4x) + 16ue^(4x)
Using these,
y2'' - 8y2' + 16y2 =
[u''e^(4x) + 8u'e^(4x) + 16ue^(4x)] - 8[u'e^(4x) + 4ue^(4x)] + 16ue^(4x) = 0
u''e^(4x) = 0
Let w = u', then w' = u''
w'e^(4x) = 0
w' = 0
Integrating this, we have
w = C1
But w = u'
u' = C1
Integrating again, we have
u = C1x
But y2 = ue^(4x)
y2 = C1xe^(4x)
And this is the second solution
Equation is given as;
y = (g/k) yo
To find the value of “k”, divide both sides of the
equation with yo;
y/yo = (g/k)yo/yo
it implies that;
y/yo = (g/k)
Now following steps will obtain the value of “k” as;
ky/yo = g
ky = gyo
<span>k = gy0/y </span>
Answer:
The answer is explained below
Step-by-step explanation:
Given that The volume of air inside a rubber ball with radius r can be found using the function V(r) = 
, this means that the volume of the air inside the rubber ball is a function of the radius of the rubber ball, that is as the radius of the rubber ball changes, also the volume of the ball changes.
As seen from the function, the radius is directly proportional to the volume of the ball, if the radius increases, the volume also increases.
is equal to the volume of the ball when the radius of the ball is 
. Therefore:
The best way to determine which among the fractions has the greatest value, convert all of them to their decimal equivalents. To do so, divide the numerator by the denominator. Conor ate 0.25 of the pizza, Brandon also 0.25, Tyler 0.75, and Audrey 0.5. Thus, the answer is letter "B. Tyler".
