We have the following dimensions:
w=wide
w+70=length
We have a right triangle:
leg₁=w
leg₂=w+70
hypotenuse=130
Pythagoras theorem:
leg₁²+leg₂²=hypotenuse²
Then:
w²+(w+70)²=130²
We have to solve that equation:
w²+(w+70)²=130²
w²+w²+140w+4900=16900
2w²+140w+4900-16900=0
2w²+140w-12000=0
(2w²+140w-12000)/2=0/2
w²+70w-6000=0
w=(-70⁺₋√(4900+24000)) / 2
=(-70⁺₋170) / 2
We have two possible solutions:
Solution 1
w=(-70-170)/2=-120 (this solution is not possible because the result is negative and it have no sense in this problem).
Solution 2
w=(-70+170)/2=50 (this is the right solution)
w=50
w+70=120
ANSWER: the length would be 120 u (u=units of length ) and the wide would be 50 u.
Answer:
Step-by-step explanation:
Given:
Scale
2 inches : 5 feet
Actual dimensions
Let x be the dimension of the scale drawing (in inches) and y, the corresponding dimension of the actual field (in feet).
Scaled dimension = scale × actual dimension
Actual dimension, x = y × 5 ft/2 in
2 × x = 5 × y
Equation:
2x = 5y
The answer is Hx = ½ Wsin θ cos θ
The explanation for this is:
Analyzing the torques on the bar, with the hinge at the axis of rotation, the formula would be: ∑T = LT – (L/2 sin θ) W = 0
So, T = 1/2 W sin θ. Analyzing the force on the bar, we have: ∑fx = Hx – T cos θ = 0Then put T into the equation, we get:∑T = LT – (L/2 sin θ) W = 0
To correctly apply the distributive property, we can multiply the parenthesized terms makong sure to have the correct positive and negative signs. Distributive the -2.1 by multiplying it by 3.4 to get -7.14 as your equivalent expression.
