Percent increase is:
Change/original * 100
(29975-24400)/24400
5575/24400= .228 * 100=
22.8%
Answer:lol can somebody please answer this I need an answer I have this question
Step-by-step explanation:
A)<span> How much would it cost to ship a package weighing 3.2 pounds? Explain how you arrived at your answer.
Answer:Shipping cost of 3.2 package is $4.13.
</span>We can't use the cost assigned to 3 lbs because the package is over 3 lbs but it is not over 4 lbs so we use the cost of 4lbs. (check the attachment for price)
b)<span>What type of graph is needed to represent the Media Mail shipping prices as a function of the weight of the books shipped? Explain your thinking.
Answer:Line graph </span>is needed to represent the Media Mail shipping prices as a function of the weight of the books shipped.
In line graph, x values represent the weight in pounds and the y values represent the cost.
c)<span>Graph the Media Mail shipping prices as a function of the weight of the books shipped.
Answer;When we g</span>raph the Media Mail shipping prices as a function of the weight of the books shipped, it will be;
f(x) = 2.69 + 0.48(x-1)
Let stadium 1 be the one on the left and stadium 2 the one on the right.
Angle above stadium 1 is 72.9° and the angle above stadium 2 is 34.1° using the angle property of alternate angles(because both the ground and the dotted line are parallel).
For the next part we need to use the trigonometric function of tangent.
As tan x = opposite / adjacent,
Tan 72.9°=1500/ adjacent ( the ground from O to stadium 1)
Therefore the adjacent is 1500/tan 72.9°= 461.46 m( to 5 s.f.)
Same for the next angle,
Tan 34.1°=1500/ adjacent ( the ground from O to stadium 2)
Therefore, the adjacent is 1500/tan 34.1° = 2215.49 m (to 5 s.f.)
Thus, the distance between both stadiums is 2215.49-461.46= 1754.03 m
Correcting the answer to whole number gives you 1754 m which is the option C.
Substitute t = 0, to get the initial height