The function f(x) is shown on the graph. On a coordinate plane, a curved line with 3 arcs, labeled f of x, crosses the x-axis at
2 answers:
Answer:
x = -2,1,3
Step-by-step explanation:
Given: The curved line represented by the function crosses the x-axis at and y-axis at
To find: value of x for which
Solution:
= gives those values of x for which the curve represented by the given function cuts the x-axis.
According to question, the curve cuts the x-axis at
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For this case, the first thing we must do is define variables.
We have then:
t: the time in minutes
k: the number of kilometers
The relationship between both variables is direct.
Therefore, the function is:
Where, "c" is a constant of proportionality.
To determine "c" we use the following data:
After running for 18 minutes, she completes 2 kilometers.
Substituting values:
Clearing c we have:
Then, the equation is given by:
Answer:
An equation that can be used to represent k, the number of kilometers Julissa runs in t minutes is:
Answer:
Decrease in temperature = 4.6714°C
Step-by-step explanation:
We know that the formula fro deflection is:
δ = PL/AE + LαΔT
As deflection is equal to zero in this case, the formula becomes
ΔT = -P/αAE -------------- equation (1)
Now,
we see that only vertical force acting is weight
W = mg = 100*9.81
W = 981N = ∑ where 1N = 1kgm/s²
Now,
for horizontal forces
As we know that, Sum of all horizontal forces = 0
P - μN = 0
P - μW = 0
P = μW
P = 0.6 * 981
P = 588.8N or 589N
Now we need to calculate the area
area = width * thickness = 20 * 3
area = 60 mm²
Now by substituting all these values in equation 1, wee get
ΔT = -P/αAE = - 588.6/(20*10⁻⁶*60*10⁻⁶*105*10⁹)
ΔT = - 4.6714°C (negative sign indicates decrease)
Correct answer is: distance from D to AB is 6cm
Solution:-
Let us assume E is the altitude drawn from D to AB.
Given that m∠ACB=120° and ABC is isosceles which means
m∠ABC=m∠BAC =
And AC= BC
Let AC=BC=x
Then from ΔACD , cos(∠ACD) =
Since DCB is a straight line m∠ACD+m∠ACB =180
m∠ACD = 180-m∠ACB = 60
Hence
Now let us consider ΔBDE, sin(∠DBE) =
