Answer:
a) There is no a word problem for both expressions (
and 
), b) A bottle contains 25.4 fluid ounces of shampoo. Katie uses 0.75 of the bottle. How much shampoo is left? A bottle contains 25.4 fluid ounces of shampoo. Katie uses 0.25 fluid ounces of the bottle. How much shampoo is left?
Step-by-step explanation:
a) The shampoo problem is a word problem for:
(Final content) = (Initial content) - (Used content)
Then,
Or:
Hence, there is no a word problem for both expressions ( and ).
b) The word problem for is:
A bottle contains 25.4 fluid ounces of shampoo. Katie uses 0.75 of the bottle. How much shampoo is left?
The word problem for is:
A bottle contains 25.4 fluid ounces of shampoo. Katie uses 0.25 fluid ounces of the bottle. How much shampoo is left?
12 problems = 30 minutes
24 problems = 60 minutes
36 problems= 90 minutes
48 problems = 120 minutes
60 problems = 150 minutes
Mary can respond 60 problems in 2 hours and 30 minutes/ 2 hours and half/ 150 minutes.
Hope this helps xx
Given that function H(t) models the height of Pooja's plant (in centimeters) where t is the number of days after she bought it.
Now we have to find about which number type is more appropriate for the domain of h. That means what values can be taken by the variable "t".
Since t is number of days not the hours so t will not use decimal or fraction values. It can use integer values for the number of days.
Since time is counted after she bought the plant then number of days will be positive.
Hence answer for the type of domain can be positive integers or you can say integers greater than or equal to 0.
<span>At least 75% of the data will fall within 2 standard deviations of the mean.
This is tricky problem. Usually when you're dealing with standard deviation, you have a bell curve, or something close to a bell curve and for such a data distribution, there will be approximately 95% of the data within 2 standard deviations of the mean. But if you don't know that you have a bell curve, you have to fall back to Chebyshev’s Theorem, which states that at least 75% of the data points will fall within 2 standard deviations of the mean for any set of numbers.</span>
Answer:
From what I can see of the problem, you CANNOT solve for the half-life of U 235 AND then solve for the length of time to determine the 20% decay.
U-235 half-life is 704,000,000 years. (Wikipedia)
The elapsed time formula = half-life * [log (Beginning Amount / ending amount) / log 2]
elapsed time = 7.04 x 10^8 * [log (100 % / 80%) / log 2]
elapsed time =7.04 x 10^8 * [log (1.25) / .30103]
elapsed time =7.04 x 10^8 * [0.096910 / .30103]
elapsed time = 7.04 x 10^8 * 0.321928047
elapsed time = 226,637,000 years
Step-by-step explanation:
