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tamaranim1 [39]
2 years ago
9

A Shampoo Problem: A bottle contains 25.4 fluid ounces of shampoo. Katie uses 0.25 of the bottle. How much shampoo is left? a. I

s the shampoo problem a word problem for 0.25 * 25.4, is it a word problem for 25.4 − 0.25, or is it not a word problem for either of these? Explain. b. Write a new shampoo word problem for 0.25 * 25.4 and write a new shampoo word problem for 25.4 − 0.25. Make clear which is which.
Mathematics
1 answer:
kotykmax [81]2 years ago
7 0

Answer:

a) There is no a word problem for both expressions (m = 0.25\cdot 25.4 and m = 25.4-0.25), b) A bottle contains 25.4 fluid ounces of shampoo. Katie uses 0.75 of the bottle. How much shampoo is left? A bottle contains 25.4 fluid ounces of shampoo. Katie uses 0.25 fluid ounces of the bottle. How much shampoo is left?

Step-by-step explanation:

a) The shampoo problem is a word problem for:

(Final content) = (Initial content) - (Used content)

Then,

m = 25.4 - 0.25\cdot 25.4

Or:

m = 0.75\cdot 25.4

Hence, there is no a word problem for both expressions (m = 0.25\cdot 25.4 and m = 25.4-0.25).

b) The word problem for m = 0.25\cdot 25.4 is:

A bottle contains 25.4 fluid ounces of shampoo. Katie uses 0.75 of the bottle. How much shampoo is left?

The word problem for m = 25.4-0.25 is:

A bottle contains 25.4 fluid ounces of shampoo. Katie uses 0.25 fluid ounces of the bottle. How much shampoo is left?

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Answer:

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Step-by-step explanation:

Given:

Cost of each apples = $0.8

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Number of fruits bought= 11

We need to find the number of apples bought and number of oranges were bought.

Solution:

Let the number of apples bought be 'a'.

Let the number of oranges were bought be 'o'.

Number of fruits bought= 11

So we can say that;

Number of fruits bought is equal to sum number of apples bought and number of oranges were bought.

framing in equation form we get;

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Now we can say that;

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framing in equation form we get;

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Now Multiplying equation 1 by 0.8 we get;

0.8(a+o)=0.8\times11

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Subtracting equation 3 from equation 2 we get;

0.8a+0.95o-(0.8a+0.8o)=9.55-8.8\\\\0.8a+0.95o-0.8a-0.8o=0.75\\\\0.15o=0.75

Dividing both side by 0.15 we get;

\frac{0.15o}{0.15}=\frac{0.75}{0.15}\\\\o=5

Substituting the value of o in equation 1 we get;

a+o=11\\\\a+5=11\\\\a=11-5=6

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