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KiRa [710]
2 years ago
14

The two-way frequency table below shows data on student behavior and the use of positive phone calls home as an incentive for go

od behavior for a group of students at Lion's Lane Elementary School.
Complete the following two-way table of row relative frequencies.
(If necessary, round your answers to the nearest hundredth.)
Desirable behavior Undesirable behavior
Phone call 19 9
No phone call 8 6

Desirable behavior Undesirable behavior Row total
Phone call 1.00
No phone call 1.00

Mathematics
1 answer:
dusya [7]2 years ago
8 0

Answer:

From the frequency table, let's calculate the row total.

Row total for phone call = 19 + 9 = 28

Row total for no phone call = 8 +6 = 14

To calculate their respective row relative frequencies, let's use:

Row relative freq = \frac{freq.}{Row total}

Now, the two-way frequency table will be computed as:

For phone call:

Desirable behavior = \frac{19}{28} = 0.67857 ≈0.69

Undesirable behaviour = \frac{9}{28} = 0.3214 ≈0.32

No phone call:

Desirable behaviour = \frac{8}{14} = 0.5714 ≈ 0.57

Undesirable behaviour = \frac{6}{14} = 0.4286 ≈ 0.43

The complete two-way table is attached.

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Three highways connect city A with city B. Two highways connect city B with city C.
QveST [7]
(a) The probability that there is no open route from A to B is (0.2)^3 = 0.008.
Therefore the probability that at least one route is open from A to B is given by: 1 - 0.008 = 0.992.
The probability that there is no open route from B to C is (0.2)^2 = 0.04.
Therefore the probability that at least one route is open from B to C is given by:
1 - 0.04 = 0.96.
The probability that at least one route is open from A to C is:
0.992\times0.96=0.9523

(b)
α The probability that at least one route is open from A to B would become 0.9984. The probability in (a) will become:0.9984\times0.96=0.95846

β The probability that at least one route is open from B to C would become 0.992. The probability in (a) will become:
0.992\times0.992=0.9841

Gamma: The probability that a highway between A and C will not be blocked in rush hour is 0.8. We need to find the probability that there is at least one route open from A to C using either a route A to B to C, or the route A to C direct. This is found by using the formula:
P(A\cup B)=P(A)+P(B)-P(A\cap B)
0.9523+0.8-(0.9523\times0.8)=0.99
Therefore building a highway direct from A to C gives the highest probability that there is at least one route open from A to C.


4 0
2 years ago
Kite A B C D is shown. Lines are drawn from point A to point C and from point B to point D and intersect. In the kite, AC = 10 a
Oduvanchick [21]

Answer:

30 u^{2}

Step-by-step explanation:

The computation of the area of kite ABCD is shown below:

Given data

AC = 10 ;

BD = 6

As we can see from the attached figure that the Kite is a quadrilateral as it involves two adjacent sides i.e to be equal

Now the area of quadrilateral when the diagonals are given

So, it is

\text { area of kite }=\frac{1}{2} \times d_{1} d_{2}

where,

d_{1}=10\ and\ d_{2}=6

So, the area of the quadrilateral is

=\frac{1}{2}(10)(6)\\\\=30 u^{2}

4 0
1 year ago
The parallel dotplots below display the girths (belly
liraira [26]

Answer:

The standard deviation for the distribution of girths is

about the same for both male and female pigs.

Step-by-step explanation:

Step 1

We will interprete the dotplots

For the Male pigs

24, 26, 26, 26, 26, 26, 26, 28, 28, 28, 28, 28, 28, 28, 28, 28, 28, 28, 30, 30, 30, 30, 30, 30, 32

Range

Maximum value - Minimum value

= 32 - 24

= 8

IQR = Interquartile range = Q3 - Q1

Q1 formula = 1/4(n + 1)th

=n = 25

= 1/4(25 + 1)

= 1/4(26)

= 26/4

= 6.5

This mean the value is between the 6th and 7th value

6th value = 26

7th value = 26

Q1 = 26 + 26/2

Q1 = 26

Q3

Q3 formula = 3/4(n + 1)th

=n = 25

= 3/4(25 + 1)

= 3/4(26)

= 78/4

= 19.5

This mean the value is between the 19th and 20th value

19th value = 30

20th value = 30

Q3= 30+ 30/2

= 30

IQR = 30 - 26

= 4

Standard deviation

Mean

First we find the mean

= 24+ 26+26+ 26+ 26+ 26+26+28+ 28+ 28+ 28+28+ 28+ 28+28+ 28+28+28+30+ 30+30+ 30+30+30+32/28

= 700/25

= 28

Standard deviation Formula = √(x - mean)²/n - 1

= √[(24-28)² + (26- 28)² + (26 -28)² + (26 - 28)² +................ (32 - 28)²]/25 - 1

= √(16 + 4 + 4+ 4+ 4+4+ 4+0+ 0+ 0+ 0+0+ 0+ 0+ 0+0+0+0+ 4+ 4+4+4+4+ 4+ 16)/25 - 1

= √80/25 - 1

=√3.333333333

1.825741858

Female Pigs

21, 23, 23, 23,23,23,23,25, 25, 25, 25, 25, 25, 25, 25, 25, 25,25, 27, 27, 27, 27,27, 27, 29

Range:

Maximum value - Minimum value

= 29 - 21

8

IQR

IQR = Interquartile range = Q3 - Q1

Q1 formula = 1/4(n + 1)th

=n = 25

= 1/4(25 + 1)

= 1/4(26)

= 26/4

= 6.5

This mean the value is between the 6th and 7th value

6th value = 23

7th value = 23

Q1 = 23 + 23/2

Q1 = 23

Q3

Q3 formula = 3/4(n + 1)th

=n = 25

= 3/4(25 + 1)

= 3/4(26)

= 78/4

= 19.5

This mean the value is between the 19th and 20th value

19th value = 27

20th value = 27

Q3= 27+ 27/2

Q3 = 27

IQR = 27 - 23

= 4

First we find the Mean

=(21+23+23+23+23+23+23+25+ 25+ 25+ 25+25+ 25+ 25+ 25+25+25+25+27+27+ 27+27+27+ 27+29)/25

= 625/25

= 25

Standard deviation Formula = √(x - mean)²/n - 1

= √[(21-25)² + (23- 25)² + (23 -25)² + (23 - 25)² +................ (29 - 25)²]/25 - 1

= √(16 + 4 + 4+ 4+ 4+4+ 4+0+ 0+ 0+ 0+0+ 0+ 0+ 0+0+0+0+ 4+ 4+4+4+4+ 4+ 16)/25 - 1

= √80/25 - 1

=√3.333333333

1.825741858

Looking at the calculation above and comparing both the girths from the male and female

We can conclude that: The standard deviation for the distribution of girths is

about the same for both male and female pigs which is 1.825741858

5 0
2 years ago
Malika charges $7.20 per hour for babysitting. She babysits 4 hours each week. She spends $10 per week and puts the rest of her
Juliette [100K]
$7.20        $28.8        $18.8        $225.6        $225.6
        4        $10              12                   .25       $56.4
X___       -_____         X____      X_____    +_____
$28.8       $18.8          225.6          $56.4        $282

You multiply $7.20 by the 4 hours she's working and you'll get $28.80. Then you would subtract the $10 from your answer and get $18.80. Then you'd multiply $18.80 by 12 for the mouths she's working and get $225.60. Next you multiply $225.60 by .25 from the grandparents and get $56.40. Finally you add $225.60 to $56.40 and get $282 in her savings account.
5 0
1 year ago
The total cost of an item including sales tax is directly proportional to its price. If the total cost of a $32 item is $33.60 ,
pav-90 [236]
Let the total cost of the item be represented by C and the price be represented by P, then given that t<span>he total cost of an item including sales tax is directly proportional to its price, thus</span>

C\propto P \\  \\ \Rightarrow C=kP

where k is a constant.

Given that <span>the total cost of a $32 item is $33.60, thus

33.60=32k \\  \\ \Rightarrow k= \frac{33.60}{32} =1.05

Therefore, the total cost on a $55 item is given by

C=1.05\times55=\$57.75</span>
3 0
2 years ago
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