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Lisa [10]
2 years ago
6

What two products would you add to find 713​x48

Mathematics
2 answers:
umka21 [38]2 years ago
5 0

9514 1404 393

Answer:

  40·713 and 8·713

Step-by-step explanation:

When this multiplication is carried out "by hand", the usual sum of partial products is ...

  8·713 + 40·713

Hoochie [10]2 years ago
5 0

Answer:

5704, 28520

Step-by-step explanation:

First find the product of 713 x 48 which is 34224. Next, we find the two products to do so we first add 713 x 8 = 5704.Then,we multiply 713 x 40 which is 28520. This strategie is multiply by the ones then by the tens and add them together to find the your answer.

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Julie rides her bike from the sports complex to the school. Then she rides from the school to the mall, and then on to the libra
user100 [1]

Answer:

Between the two persons presented above, Julie had ridden farther.  

Step-by-step explanation:

This is because from the routes she had taken, she would be covering greater distance compared to Kyle. Julie still ad to ride from the complex to school.

4 0
2 years ago
A lock has two buttons: a "0" button and a "1" button.To open a door you need to push the buttons according to a preset 8-bit se
ratelena [41]

Answer:

Step-by-step explanation:

The problem relates to filling 8 vacant positions by either 0 or 1

each position can be filled by 2 ways so no of permutation

= 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2

= 256

b )

Probability of opening of lock in first arbitrary attempt

= 1 / 256

c ) If first fails , there are remaining 255 permutations , so

probability of opening the lock in second arbitrary attempt

= 1 / 255 .

7 0
2 years ago
the diameter of a football is five times the diameter of a cricket ball ratio of surface area of football and cricket ball is​
LenKa [72]

Answer:

25 : 1

Step-by-step explanation:

The diameter of the football is 5 times the diameter of the cricket ball. This means that the radius of the football is also 5 times the radius of the cricket ball.

Let the radius of the football be R.

Let the radius of the cricket ball be r.

This implies that:

R = 5r

Both balls are spherical.

The surface area of the cricket ball is given as:

a = 4\pi r^2

The surface area of the football is given as:

A = 4\pi R^2

=>A = 4\pi (5r)^2\\\\A = 100\pi r^2

Therefore, the ratio of their surface areas is:

A : a

100\pi r^2 : 4\pi r^2

= 100 : 4

25 : 1

5 0
2 years ago
The owners of Prim's Pizza are concerned that many of their customers are starting to purchase pizza from The Pizza Palace becau
AleksandrR [38]

Answer:

(240-210) -1.984 \sqrt{\frac{8.6^2}{100}+\frac{5.7^2}{100}}=27.953

(240-210) +1.984 \sqrt{\frac{8.6^2}{100}+\frac{5.7^2}{100}}=32.047

And the confidence interval for the difference is between:

27.953 \leq \mu_1 -\mu_2 \leq 32.047

Step-by-step explanation:

We have the following info given:

\bar X_1 = 240 sample mean for medium Pizzas from Prim's

\bar X_2 = 210 sample mean for medium Pizzas from Pizza Place

s_1 =8.6 sample deviation for Prim's

s_2 =5.7 sample deviation for Pizza Palca

n_1 =n_2 = 100  sample size selected for each case

The confidence interval for the difference of means is given by:

(\bar X_1 -\bar X_2) \pm t_{\alpha/2}\sqrt{\frac{s^2_1}{n_1} +\frac{s^2_2}{n_2}}

And for the 95% confidence we need a significance level of \alpha=1-0.95=0.05 and \alpha/2 =0.025, the degrees of freedom are given by:

df= n_1 +n_2 -2= 100+100-2 =98

And the critical value would be

t_{\alpha/2}= 1.984

And replacing we got:

(240-210) -1.984 \sqrt{\frac{8.6^2}{100}+\frac{5.7^2}{100}}=27.953

(240-210) +1.984 \sqrt{\frac{8.6^2}{100}+\frac{5.7^2}{100}}=32.047

And the confidence interval for the difference is between:

27.953 \leq \mu_1 -\mu_2 \leq 32.047

8 0
2 years ago
Which of the following values for m proves that 2m + 2m is not equivalent to 4m2?
Mashutka [201]
M=0 i am not sure it is right 
6 0
2 years ago
Read 2 more answers
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