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In-s [12.5K]
2 years ago
13

The figure shows a map of five streets that meet at Concord Circle. The measure of the angle formed by Melville Road and Emerson

Avenue is 119°. The measure of the angle formed by Emerson Avenue and Thoreau Street is 135°. Hawthorne Lane bisects the angle formed by Melville Road and Emerson Avenue. Dickinson Drive bisects the angle formed by Emerson Avenue and Thoreau Street. What is the measure of the angle formed by Hawthorne Lane and Dickinson Drive?     The measure of the angle formed by Hawthorne Lane and Dickinson Drive is °.
Mathematics
2 answers:
DiKsa [7]2 years ago
4 0
Do you have a picture?
Vikentia [17]2 years ago
3 0

126 degreees since H ad d r the bisectors you cut them in half and you would get the bisectors then just add them tegtehr



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2: Row 2

3:6 and 10

Step-by-step explanation:

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Recently, 18.3% of visitors to the travelocity web site hailed from the google search engine. a random sample of 130 visitors on
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In your problem:
p = 18.3% = 0.183
n = 130

The standard error can be calculated by the formula:
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2 years ago
If h(x) = 6 - X, what is the value of (h*n (10)?
faltersainse [42]

Answer:

<u>(h * h)(10) = 16</u>

Step-by-step explanation:

We should know that: (f*g)(x) = f(x)*g(x)

Given:   h(x) = 6 - x

∴(h * h)(x) = (6-x) (6-x) = (6-x)²

To find (h * h)(10), substitute with x = 10 at (h * h)(x)

∴ (h * h)(10) =  (6-10)² = (-4)² = 16

==============================================

Note: if we want to find (hoh)(10)

(hoh)(x) = h[h(x)] = 6 - (6 - x) = 6 - 6 + x = x

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8 0
2 years ago
Two armadillos and three aardvarks sat in a five-seat row at the Animal Auditorium. What is the probability that the two animals
Serhud [2]

Answer:

      \dfrac{1}{15}

Explanation:

The number of different ways in which the<em> two armadillos</em> would be at the ends of the row is 2:

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The number of different combinations in which<em> two of the three aardvarks </em>can sit at the ends of the row is P(3,2):

          P(3,2)=\dfrac{3!}{(3-2)!}=\dfrac{3\times 2\times 1}{1}=6

Therefore, there are 2 + 6 = 8 different ways in which the two animlas on the ends of the row were both armadillos or both aardvarks.

Now calculate the total number of different ways in which the animals can sit. It is P(5,5):

        P(5,5)=\dfrac{5!}{(5-5)!}=5!=5\times 4\times 3\times 2\times 1=120

Thus, <em>the probability that the two animals on the ends of the row were both armadillos or both aardvarks</em> is equal to the number of favorable outputs divided by the total number of possible outputs:

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8 0
1 year ago
Consider the inverse function. Which conclusions can be drawn about f(x) = x2 + 2? Select three options. f(x) has a limited rang
PolarNik [594]

Answer:

f(x) has a limited range

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Step-by-step explanation:

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f(x) = x^2+2

The domain is the value of the input variables for which the function will exist. According to the expression given, the function exists on all real values of x. The same goes with range which deals with the output values. It also exists on all real values from 2 and above.

Hence f(x) have a limited range (since values less than 2 are not included compare to domain that exists on all real values) and does not have a restricted domain.

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substitute y = 0 into the function and get y

if y = f(x)

y = x^2+2

0 = x^2 + 2

x^2 = -2

x = 2i

Hence  f(x) does not have an x-intercept of (2, 0)

For the y intercept, y intercept occur at x = 0

substitute x = 0 into the function and get y

if y = f(x)

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Hence  f(x) has a y-intercept at point (0, 2)

f(x) is at maximum if d(fx))/dx = 0

d(fx))/dx  = 2x

since  d(fx))/dx  = 0

0 = 2x

x = 0

substitute x = 0 into the function

f(x) = x^2 + 2

y = 0^2+2

y = 2

Hence f(x) has a maximum at the point (0, 2)

5 0
1 year ago
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