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zhenek [66]
2 years ago
6

Which value of x is in the solution set of 2x-3>11-5x

Mathematics
3 answers:
Serhud [2]2 years ago
8 0

7x>14,x=2። is right answer i think

kipiarov [429]2 years ago
4 0

Answer:

Value of x > 2 is in the solution set of 2x-3>11-5x which means the value of x can be any value greater than 2.

Step-by-step explanation:

We need to find the value of x for the equation 2x-3>11-5x

2x-3>11-5x

Adding +5x on both sides:

2x+5x-3>11-5x+5x

7x-3>11

Adding +3 on both sides

7x-3+3>11+3

7x>14

Dividing by 7 on both sides:

7x/7>14/7

x>2

Value of x > 2 is in the solution set of 2x-3>11-5x which means the value of x can be any value greater than 2.

Ierofanga [76]2 years ago
3 0

7x>14,x=2። is right answer i think

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Answer:

$99

Step-by-step explanation:

Cost of electricity per year= $165

Tax per month= 5%

Amount of tax paid per month= 5% of $165

= 0.05 × 165

= $8.25

Ella's family pays $8.25 tax per month

There are 12 months in 1 year

Ella's family will pay Ina year = $8.25 × 12

= $99

Ella's family will pay $99 tax for an entire year

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Hope this is what you need

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The graph of the parent function f(x) = x2 is dashed and the graph of the transformed function g(x) = (x – h)2 is solid. Use the
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If h=-5 the vertex is shifted to (-5,0)

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Сумму чисел 165 и 633 уменьшили в несколько раз получили 266. Чему равно неизвестное число?
Whitepunk [10]

Answer:

3

Step-by-step explanation:

The sum of 165 and 633 will be

165+633=798

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Therefore, as per the question, this sum was reduced three different times

4 0
2 years ago
Of the 500 sample households in the previous exercise, 7 had three or more large-screen TVs. (a) The percentage of households in
likoan [24]

Answer:

a) The percentage of households in the town with three or more largescreen TVs is estimated as :

The best estimation for the population proportion is :

\hat p=\frac{7}{500}=0.014

And that represent the 1.4%.

b) And the 95% confidence interval would be given (0.00370;0.0243).

And the % would be between 0.37% and 2.43%.

Step-by-step explanation:

Data given and notation  

n=500 represent the random sample taken    

X=7 represent the households with three or more large-screen TVs

\hat p=\frac{7}{500}=0.014 estimated proportion of households with three or more large-screen TVs

\alpha=0.05 represent the significance level (no given, but is assumed)    

z would represent the statistic (variable of interest)    

p= population proportion of households with three or more large-screen TVs

Part a

The percentage of households in the town with three or more largescreen TVs is estimated as :

The best estimation for the population proportion is :

\hat p=\frac{7}{500}=0.014

And that represent the 1.4%.

Part b

Yes is possible. We hav that np>10 and n(1-p)>10 so we have the assumption of normality to find the interval.

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 95% confidence interval the value of \alpha=1-0.95=0.05 and \alpha/2=0.025, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=1.96

And replacing into the confidence interval formula we got:

0.014 - 1.96 \sqrt{\frac{0.014(1-0.014)}{500}}=0.00370

0.014 + 1.96 \sqrt{\frac{0.014(1-0.014)}{500}}=0.0243

And the 95% confidence interval would be given (0.00370;0.0243).

And the % would be between 0.37% and 2.43%.

4 0
2 years ago
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