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zhenek [66]
1 year ago
6

Which value of x is in the solution set of 2x-3>11-5x

Mathematics
3 answers:
Serhud [2]1 year ago
8 0

7x>14,x=2። is right answer i think

kipiarov [429]1 year ago
4 0

Answer:

Value of x > 2 is in the solution set of 2x-3>11-5x which means the value of x can be any value greater than 2.

Step-by-step explanation:

We need to find the value of x for the equation 2x-3>11-5x

2x-3>11-5x

Adding +5x on both sides:

2x+5x-3>11-5x+5x

7x-3>11

Adding +3 on both sides

7x-3+3>11+3

7x>14

Dividing by 7 on both sides:

7x/7>14/7

x>2

Value of x > 2 is in the solution set of 2x-3>11-5x which means the value of x can be any value greater than 2.

Ierofanga [76]1 year ago
3 0

7x>14,x=2። is right answer i think

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Answer:

<em>50 Chef's salads and 50 Caesar salads should be prepared in order to maximize profit.</em>

Step-by-step explanation:

Suppose, the number of Chef's salad is x and the number of Caesar salad is y

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So, the two constraints are:  40\leq x\leq 60 and  35\leq y\leq 50

The total number sold has never exceed 100 salads. So, another constraint will be:   x+y\leq 100

According to the graph of the constraints, the vertices of the common shaded region are:  (40,35), (60,35), (60,40), (50,50) and (40,50)   <em>(Refer to the attached image for the graph)</em>

The lunch stand makes a $.75 profit on each Chef's salad and $1.20 profit on each Caesar salad. So, the profit function will be:  P=0.75x+1.20y

For  (40, 35) ,   P=0.75(40)+1.20(35)=72

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For  (60, 40) ,   P=0.75(60)+1.20(40)=93

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For  (40, 50) ,   P=0.75(40)+1.20(50)=90

Profit will be maximum when x=50 and y=50

Thus, 50 Chef's salads and 50 Caesar salads should be prepared in order to maximize profit.

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