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IgorLugansk [536]
2 years ago
10

Hurry When solving a system of equations, Jared found y = x 10 for one equation and substituted x 10 for y in the other equation

. Nicole found x = y – 10 for the same equation and substituted y – 10 for x in the other equation. Who is correct? Explain.
Mathematics
2 answers:
Galina-37 [17]2 years ago
8 0

Answer:

Both Jared and Nicole are correct. You can solve for either variable and use the equivalent expression to create a one-variable equation. Then you can solve. Jared would have created a one-variable equation that can be used to solve for x, whereas Nicole would have created a one-variable equation that can be used to solve for y.

Step-by-step explanation:

this is the sample response

Aloiza [94]2 years ago
4 0
I can say that Jared and Nicole are correct because they manipulated the equation right. They can either write the equation as y as a function of x then substitute it to the y in the other equation and solve for x. They can also write the equation as x as a function of y and substitute it to x in the other equation and solve for y. For both solution, they will still obtain the same answers.
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Stan made 24 sales in 6 hours . what is the ratio of sales to hours?
Furkat [3]
Let s = sale

Let h = hours

The ratio is s to h, which can be written as a fraction as 24/6.
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2 years ago
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Sides AB and DC of the rectangle are increased in length by 50% and sides AD and BC are decreased in length by 50%. What is the
emmainna [20.7K]

The percentage of change in the area of the rectangle is -25% ⇒ B

Step-by-step explanation:

The given is:

  • Sides AB and DC of the rectangle are increased in length by 50%
  • Sides AD and BC are decreased in length by 50%

We need to find the percentage change in the <em>AREA</em> of the rectangle

Assume that the length of AB ans DC is x units, and the length of AD and BC is y units

∵ The length of the sides AB and DC increased by 50%

∵ The length of AB and CD = x

- That means x will increase by 50% of x

∵ 50% of x = (50 ÷ 100) × x = 0.5 x

∴ The length is increased by 0.5 x

∴ The new length of AB and CD = x + 0.5 x = 1.5 x units

∵ The length of the sides BC and AD decreased by 50%

∵ The length of BC and AD = y

- That means y will decrease by 50% of y

∵ 50% of y = (50 ÷ 100) × y = 0.5 y

∴ The length is decreased by 0.5 y

∴ The new length of BC and AD = y - 0.5 y = 0.5 y units

∵ The area before the change = x × y = xy units²

∵ The area after the change = 1.5 x × 0.5 y = 0.75 xy units²

∵ The new area is less than the old area

∴ The area is decreased

- To find the the percentage of change in the area subtract the

   new area from the old area and divide the difference by the

    old area and then multiply the quotient by 100%

∴ The percentage of the change = \frac{xy-0.75xy}{xy} × 100%

∴ The percentage of the change = \frac{0.25xy}{xy} × 100%

∴ The percentage of the change = 0.25 × 100%

∴ The percentage of the change = 25%

∴ The area of the rectangle is decreased by 25% ⇒ (-25%)

The percentage of change in the area of the rectangle is -25%

Learn more:

You can learn more about the percentage in brainly.com/question/12960754

#LearnwithBrainly

7 0
2 years ago
Consider a sample with data values of 27, 25, 20, 15, 30, 34, 28, and 25. Compute the range, interquartile range, variance, and
Valentin [98]

So we have a set of integers,

X=\{15,20,25,25,27,28,30,34\}

And we need to compute some stats.

First the range,

The range of data set is difference between the maximum and the minimum of the data set.

So the minimum is 15 and maximum is 34 therefore the range is 34 - 15 = 19.

Second the interquartile range,

The interquartile range of data set is the difference of the first and third quartiles.

First quartile is the value separating the lower quarter and higher three - quarters of the set. The first quartile is computed by taking median of the lower half of the sorted set. This is 15, 20, 25, 25 and it's median is 22.5

Third quartile is therefore the median of 27, 28, 30, 34 which is 29.

Next up, variance.

The variance of set measures how much data is spread out. For data set x_1,\dots, x_n with an average a,

\mathsf{var}(X)=\Sigma_{i=1}^{n}\dfrac{(x_i-a)^2}{n-1}

So first compute the average value which is actually a mean,

a=\dfrac{1}{2}\Sigma_{i=1}^{n}a_i

The sum \Sigma_{i=1}^{n}a_i of numbers in set is 204.

Divide this by number of elements in the set (8).

a=\dfrac{204}{8}=25.5

Then compute the variance,

\mathsf{var}(X)=\dfrac{\Sigma_{i=1}^{n}(x_i-a)^2}{n-1}\approx\boxed{34.57}

And finally standard deviation,

Since have computed variance the standard deviation is nothing too hard. It's defined as a square root of variance,

\mathsf{sde}(X)=\sqrt{\dfrac{\Sigma_{i=1}^{n}(x_i-a)^2}{n-1}}=\sqrt{34.57}\approx\boxed{5.88}

Hope this helps.

r3t40

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Which number is greater than (&gt;) 6.841?
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6.842 or higher. When you line up the decimals, you see 6.842 has a 2 and 6.841 has a 1. 2 is greater than 1, more greater numbers are 6.843, 6.844, 6.845, etc.
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baherus [9]

angle T would be half the arc length of RQ

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