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Gelneren [198K]

2 years ago

13

Casey needed to move 23 huge boxes from his truck to the loading dock. His forklift could only hold three boxes at once. How man

y times did Casey have to visit the loading dock?

1 answer:

miss Akunina [59]2 years ago

6 0

Answer:

8

Step-by-step explanation:

Since the forklift has a maximum capacity of three boxes per trip, simply divide the total number of boxes (23 boxes) by three and round up to the nearest whole unit to find the number of trips required:

$n=\frac{23}{3}=7.667$

Casey had to visit the dock 8 times. He moved three boxes in seven trips and two boxes in one trip.

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I WILL AWARD BRAINLIEST!! PLEASE HELP!!

bezimeni [28]

Answer:

Part 1) $A(57/7,9),B(4,16/5), m=7/5$

Part 2) $A(-7,6),B(9,-6/7), m=-3/7$

Part 3) $A(80/3,9),B(5,2.5), m=0.3$

Part 4) $A(-10/63,1/3),B(2/3,-22/90), m=-0.7$

Part 5) $A(-1/5,7),B(8,48), m=5$

Step-by-step explanation:

we know that

The equation of the line into slope intercept form is equal to

$y=mx+b$

where

m is the slope

b is the y-coordinate of the y-intercept

Part 1) we have

$7x-5y=12$

step 1

Find the slope

$7x-5y=12$

isolate the variable y

$y=(7/5)x-(12/5)$

so

the slope is $m=(7/5)$

step 2

Find the missing coordinate of point A

To find the x-coordinate of point A substitute the value of y-coordinate in the equation

$9=(7/5)x-(12/5)$

$(7/5)x=9+(12/5)$

$(7/5)x=(57/5)$

$x=(57/7)$

step 3

Find the missing coordinate of point B

To find the y-coordinate of point B substitute the value of x-coordinate in the equation

$y=(7/5)(4)-(12/5)$

$y=(28/5)-(12/5)$

$y=(16/5)$

Part 2) we have

$y=-(3/7)x+3$

step 1

Find the slope

the slope is $m=-(3/7)$

step 2

Find the missing coordinate of point A

To find the x-coordinate of point A substitute the value of y-coordinate in the equation

$6=-(3/7)x+3$

$(3/7)x=3-6$

$(3/7)x=-3$

$x=-7$

step 3

Find the missing coordinate of point B

To find the y-coordinate of point B substitute the value of x-coordinate in the equation

$y=-(3/7)(9)+3$

$y=-(27/7)+3$

$y=-(6/7)$

Part 3) we have

$y=0.3x+1$

step 1

Find the slope

the slope is $m=0.3$

step 2

Find the missing coordinate of point A

To find the x-coordinate of point A substitute the value of y-coordinate in the equation

$9=0.3x+1$

$0.3x=9-1$

$0.3x=8$

$x=80/3$

step 3

Find the missing coordinate of point B

To find the y-coordinate of point B substitute the value of x-coordinate in the equation

$y=0.3(5)+1$

$y=2.5$

Part 4) we have

$6.3x+9y=2$

step 1

Find the slope

$6.3x+9y=2$

isolate the variable y

$y=-(0.7)x+(2/9)$

so

the slope is $m=-0.7$

step 2

Find the missing coordinate of point A

To find the x-coordinate of point A substitute the value of y-coordinate in the equation

$(1/3)=-(0.7)x+(2/9)$

$(0.7)x=(2/9)-(1/3)$

$(0.7)x=(2/9)-(1/3)$

$(0.7)x=-(1/9)$

$x=-(10/63)$

step 3

Find the missing coordinate of point B

To find the y-coordinate of point B substitute the value of x-coordinate in the equation

$y=-(0.7)(2/3)+(2/9)$

$y=-(14/30)+(2/9)$

$y=-(22/90)$

Part 5) we have

$y-5x=8$

step 1

Find the slope

$y-5x=8$ -------> $y=5x+8$

the slope is $m=5$

step 2

Find the missing coordinate of point A

To find the x-coordinate of point A substitute the value of y-coordinate in the equation

$7=5x+8$

$5x=7-8$

$x=-1/5$

step 3

Find the missing coordinate of point B

To find the y-coordinate of point B substitute the value of x-coordinate in the equation

$y=5(8)+8$

$y=48$

6 0

2 years ago

Xavier has $23.50 in his savings account. He deposits $35 every week. His mother also deposits $20 into the account every time X

andrezito [222]

Part A the coefficient is 20c and 35w, the variable is c and w representing cost and week. and the constant is 23.50.

Part B He would have 503.50 because <span><span>35</span><span>(12)</span></span>+60<span>=<span><span>420x</span>+<span>60+23.50 which would be 503.50

Part C The coefficient of the cost would change because you would be adding a 5 dollar increase!!!!!! done</span></span></span>

8 0

2 years ago

In two or more complete sentences, describe the transformation(s) that take place on the parent function, f(x) = log(x), to achi

lubasha [3.4K]

Answer:

Shift 2 unit left

Flip the graph about y-axis

Stretch horizontally by factor 2

Shift vertically up by 2 units

Step-by-step explanation:

Given:

Parent function: $f(x)=\log x$

Transformation function: $f(x)=\log(-2x-4)+2$

Take -2 common from transform function f(x)

$f(x)=\log[-2(x+2)]+2$

Now we see the step-by-step translation

$f(x)=\log x$

Shift 2 unit left ( x → x+2 )

$f(x)=\log(x+2)$

Flip the graph about y-axis ( (x+2) → - (x+2) )

$f(x)=\log[-(x+2)]$

Stretch horizontally by factor 2 [ -x(x+2) → -2(x+2) ]

$f(x)=\log[-2(x+2)]$

Shift vertically up by 2 units [ f(x) → f(x) + 2 ]

$f(x)=\log[-2(x+2)]+2$

Simplify the function:

$f(x)=\log(-2x-4)+2$

Hence, Using four step of transformation to get new function $f(x)=\log(-2x-4)+2$

3 0

2 years ago

Read 2 more answers

∠E and ∠F are vertical angles with m∠E=5x+10 and m∠F=7x−12 .<br><br> What is the value of x?

In-s [12.5K]

Vertical angles are equal...so set ur angles equal to each other and solve for x

5x + 10 = 7x - 12
12 + 10 = 7x - 5x
22 = 2x
22/2 = x
11 = x <==

6 0

2 years ago

Identify the segment bisector of JK

nordsb [41]

Answer:

A segment whose length is 9 units.

Step-by-step explanation:

A segment whose length is 9 units.

All we have is a bisection that divides equally segment JK in two parts. And M is the Midpoint what reassures us that JM=MK, so plugging in:

3x+15=8x+25

3x-8x=25-15

-5x=10

5x=-10

x=-2

JM=3(-2)+15 =9

MK=8(-2)+25=9

4 0

2 years ago