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HACTEHA [7]
1 year ago
11

A student writes an incorrect step while checking if the sum of the measures of the two remote interior angles of triangle ABC b

elow is equal to the measure of the exterior angle. A triangle ABC is shown. The base of the triangle extends into a straight line. The angle formed between this straight line and the edge of the triangle is marked as p. The angle adjacent to p is marked as o, and the other two angles inside the triangle are marked as m and n. Step 1: m∠m + m∠n + m∠p = 180 degrees (sum of angles of a triangle) Step 2: m∠p + m∠o = 180 degrees (adjacent supplementary angles) Step 3: Therefore, m∠m + m∠n + m∠o = m∠o + m∠p Step 4: So, m∠m + m∠n = m∠p In which step did the student first make a mistake and how can it be corrected? Step 1; it should be m∠m + m∠n + m∠o = 180 degrees (sum of angles in a triangle) Step 1; it should be m∠m + m∠n + m∠o = 90 degrees (adjacent angles) Step 2; it should be m∠o + m∠p = 180 degrees (alternate exterior angles) Step 2; m∠p − m∠o = 90 degrees (alternate interior angles)
Mathematics
1 answer:
Lady bird [3.3K]1 year ago
4 0

Answer:

(A)Step 1; it should be m∠m + m∠n + m∠o = 180 degrees (sum of angles in a triangle)

Step-by-step explanation:

  • In the triangle, the exterior angle = p
  • The adjacent interior angle =o
  • The two opposite angles are marked m and n

The steps followed by the student are:

Step 1: m∠m + m∠n + m∠p = 180 degrees (sum of angles of a triangle)

Step 2: m∠p + m∠o = 180 degrees (adjacent supplementary angles)

Step 3: Therefore, m∠m + m∠n + m∠o = m∠o + m∠p

Step 4: So, m∠m + m∠n = m∠p

We observe that the student made a mistake in Step 1, it should be m∠m + m∠n + m∠o = 180 degrees (sum of angles in a triangle).

p is outside the triangle, therefore it cannot form one of the angles in the triangle.

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Two sides of a triangle have lengths 12 m and 14 m. The angle between them is increasing at a rate of 2°/min. How fast is the le
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Answer:

1.692 m/min

Step-by-step explanation:

Let \theta be the angle between the two sides and x be the length of the third side. By cosine rule,

x^2 = 12^2+14^2-2\times12\times14\cos\theta = 340 - 336\cos\theta

x= \sqrt{340 - 336\cos\theta}

We differentiate x with respect to \theta by applying chain rule.

\dfrac{dx}{d\theta} = \dfrac{336\sin\theta}{2\sqrt{340 - 336\cos\theta}} = \dfrac{168\sin\theta}{\sqrt{340 - 336\cos\theta}}

Rate of change of \theta is 2

\dfrac{\theta}{dt} = 2

Rate of change of x is

\dfrac{dx}{dt} = \dfrac{dx}{d\theta}\times\dfrac{d\theta}{dt}

\dfrac{dx}{dt} = \dfrac{168\sin\theta}{\sqrt{340 - 336\cos\theta}} \times2=\dfrac{336\sin\theta}{\sqrt{340 - 336\cos\theta}}

At 60°,

\dfrac{dx}{dt} = \dfrac{336\sin60}{\sqrt{340 - 336\cos60}} = 1.692 \text{ m/min}

4 0
1 year ago
Andrew believes the honor roll students at his school have an unfair advantage in being assigned to the math class they request.
Artist 52 [7]
<span>                                                            Honor roll Not on honor roll Total
Received math class requested        315               64                   379
Did not get math class requested        41               80                   121
Total                                                        356             144                   500 

Honor roll: request granted: 315/356 = 0.88 x 100% = 88%
Not Honor roll request granted: 64/144 = 0.44 x 100% = 44%

Honor roll students were given preference in granting request than those not in the honor roll.</span>
5 0
1 year ago
A high school coach needs to buy new athletic shorts for the 15 members of the basketball team. The coach must spend less than $
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If the budget is $200 and he have 15 members then we have divide the two. 200 / 15 = $13.33 per shorts. 15x =< $200. x represents 13.33. So the solution represents the coach may spend up to $13.33 per pair of shorts. If it was even 1 cent more than $13.33 than he wouldn't have enough.So he can spend up to $13.33 or less per pair of shorts.
5 0
2 years ago
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High-power experimental engines are being developed by the Stevens Motor Company for use in its new sports coupe. The engineers
mamaluj [8]

Answer:

The 95% confidence interval the average maximum power is (596.0 to 644.0)

Step-by-step explanation:

Average maximum of the sample = x = 620 HP

Standard Deviation = s = 45 HP

Sample size = n = 16

We have to calculate the 95% confidence interval. The value of Population standard deviation is unknown, and value of sample standard deviation is known. Therefore, we will use one sample t-test to build the confidence interval.

Degrees of freedom = df = n - 1 = 15

Critical t-value associated with 95% confidence interval and 15 degrees of freedom, as seen from t-table = t_{\frac{\alpha}{2}} = 2.131

The formula to calculate the confidence interval is:

(x-t_{\frac{\alpha}{2} } \times \frac{s}{\sqrt{n} }, x+t_{\frac{\alpha}{2} } \times \frac{s}{\sqrt{n} })

We have all the required values. Substituting them in the above expression, we get:

(620-2.131 \times \frac{45}{\sqrt{16} }, 620+2.131 \times \frac{45}{\sqrt{16} })\\\\ =(596.0 , 644.0)

Thus, the 95% confidence interval the average maximum power is (596.0 to 644.0)

7 0
2 years ago
Roger and rita each drive at a constant speed between phoenix and san diego. Each driver’s distance for the same section of the
never [62]

Answer:

a)Rita had a 28-mile head start

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The multiple options have been added in the additional information below the problem statement.

<u>Missing Information:</u>

Since the distance of each driver is not displayed. Let us assume their distances.

Say,

Roger travelled distance = 60 miles

Rita travelled distance = 32 miles

Now as it is given in the problem statement that Roger and Rita both drove at a constant speed between Phoenix and San Diego and they drove "Same Section of the trip" .

Which Means that the distance travelled of both is between Phoenix and San Diego, just their starting points are different but their end point is the same which is San Diego.

<em><u>As we can see RIta had to cover less miles which means she got the head start, now to calculate how much of a head start she got, we need:</u></em>

Head Start Rita got = Distance Roger travelled - Distance Rita Travelled

Head Start Rita got = 60 - 32 = 28 miles

So,

Rita got a Head start of 28 miles which is option (a)

5 0
2 years ago
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