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HACTEHA [7]
1 year ago
11

A student writes an incorrect step while checking if the sum of the measures of the two remote interior angles of triangle ABC b

elow is equal to the measure of the exterior angle. A triangle ABC is shown. The base of the triangle extends into a straight line. The angle formed between this straight line and the edge of the triangle is marked as p. The angle adjacent to p is marked as o, and the other two angles inside the triangle are marked as m and n. Step 1: m∠m + m∠n + m∠p = 180 degrees (sum of angles of a triangle) Step 2: m∠p + m∠o = 180 degrees (adjacent supplementary angles) Step 3: Therefore, m∠m + m∠n + m∠o = m∠o + m∠p Step 4: So, m∠m + m∠n = m∠p In which step did the student first make a mistake and how can it be corrected? Step 1; it should be m∠m + m∠n + m∠o = 180 degrees (sum of angles in a triangle) Step 1; it should be m∠m + m∠n + m∠o = 90 degrees (adjacent angles) Step 2; it should be m∠o + m∠p = 180 degrees (alternate exterior angles) Step 2; m∠p − m∠o = 90 degrees (alternate interior angles)
Mathematics
1 answer:
Lady bird [3.3K]1 year ago
4 0

Answer:

(A)Step 1; it should be m∠m + m∠n + m∠o = 180 degrees (sum of angles in a triangle)

Step-by-step explanation:

  • In the triangle, the exterior angle = p
  • The adjacent interior angle =o
  • The two opposite angles are marked m and n

The steps followed by the student are:

Step 1: m∠m + m∠n + m∠p = 180 degrees (sum of angles of a triangle)

Step 2: m∠p + m∠o = 180 degrees (adjacent supplementary angles)

Step 3: Therefore, m∠m + m∠n + m∠o = m∠o + m∠p

Step 4: So, m∠m + m∠n = m∠p

We observe that the student made a mistake in Step 1, it should be m∠m + m∠n + m∠o = 180 degrees (sum of angles in a triangle).

p is outside the triangle, therefore it cannot form one of the angles in the triangle.

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Answer: THE GRAPH IS ATTACHED.

Step-by-step explanation:

We know that the lines are:

x + 3y=-3

y = \frac{1}{2} x + 1

Solving for "y" from the first line, we get:

3y=-x-3\\\\y=-\frac{x}{3}-1

In order to graph them, we can find the x-intercepts and the y-intercepts.

For the line x + 3y=-3 the x-intercepts is:

0=-\frac{x}{3}-1\\\\(1)(-3)=x\\\\x=-3

And the y-intercept is:

y=-\frac{0}{3}-1\\\\y=-1

For the line y=\frac{1}{2} x + 1 the x-intercepts is:

0=\frac{1}{2} x + 1\\\\-1(2)=x\\\\x=-2

And the y-intercept is:

y=\frac{1}{2} (0)+ 1\\\\y=1

 Now we can graph both lines, as you can observe in the image attached (The symbols and > indicates that the lines must be dashed).

By definition, the solution is the intersection region of all the solutions in the system of inequalities.

6 0
1 year ago
Read 2 more answers
Determine the value of (tangent of 88 degrees, 22 minutes, and 45 seconds). In this case, minutes are 1/60 of a degree and secon
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Answer:

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Step-by-step explanation:

As with many problems of this nature, you only need to get close to be able to choose the correct answer. 22 minutes 45 seconds is just slightly less than 1/2 degree (30 minutes), so the tangent value will be just slightly less than tan(88.5°) ≈ 38. The appropriate choice is 35.34015106.

If you need confirmation, you can find tan(88°) ≈ 29, so you know the answer will be between 29 and 38.

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The above has to do with strategies for choosing answers on multiple-choice problems. Below, we will work the problem.

The angle is (in degrees) ...

  88 + 22/60 +45/3600 = 88 + (22·60 +45)/3600 = 88 +1365/3600

  ≈ 88.3791666... (repeating) . . . . degrees

A calculator tells you the tangent of that is ...

  tan(88.3791666...°) ≈ 35.3401510614

Many calculators will round that to 10 digits, as in the answer above. Others can give a value correct to 32 digits. Spreadsheet values will often be correct to 15 or 16 digits.

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2 years ago
Bob has a standard deck of playing cards. If he randomly draws a J, K, 2, and 2, what is the probability that the next card he d
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A group of students estimated the length of one minute without reference to a watch or​ clock, and the times​ (seconds) are list
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Answer:

Step-by-step explanation:

Given that a group of students estimated the length of one minute without reference to a watch or​ clock, and the times​ (seconds) are listed below.

Data set is as ollows:

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H0: mu = 60 sec

Ha: mu not equals 60 sec

Mean diff = 2.27

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Test statistic = 2.27/SE =0.4815

p value =0.6376

Since p>0.05, we accept null hypothesis

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