Answer:
<h2>The answer is 0.23(approx).</h2>
Step-by-step explanation:
The given die is a three sided die, hence, there are only three possibilities of getting the outcomes.
We need to find the probability of getting exactly 3s as the result.
From the sequence of 6 independent rolls, 2 rolls can be chosen in
ways.
The probability of getting two 3 as outcome is
.
In the rest of the 4 sequences, will not be any 3 as outcome.
Probability of not getting a outcome rather than 3 is
.
Hence, the required probability is
≅0.2966 or, 0.23.
We are given
piggy bank has nickels , dimes and quarters
Let's assume
number of nickels =n
every two nickels there are 3 dimes
so, number of dimes are


every two dimes that are 5 quarters there
so, number of quarters are


so, total number of coins = number of nickels + number of dimes +number of quarters
total number of coins =n+1.5n+3.75
there are 500 coins
so, we get

now, we can solve for n

divide both sides by 6.25
so, we get

number of dimes is 1.5n


number of quarters is 3.75n


so,
Number of nickels =80
Number of dimes =120
Number of quarters =300............Answer
Answer:
Sinister Stan needs 1/40 oz more slime for his evil plan.
Step-by-step explanation:
6 3/8-3 3/4-2 3/5 = 51/8-15/4-13/5 = 255/40-150/40-104/40 = 1/40
Answer: 0.05
Step-by-step explanation:
Let M = Event of getting an A in Marketing class.
S = Event of getting an A in Spanish class,
i.e. P(M) = 0.80 , P(S) = 0.60 and P(M∩S)=0.45
Required probability = P(neither M nor S)
= P(M'∩S')
= P(M∪S)' [∵P(A'∩B')=P(A∪B)']
=1- P(M∪S) [∵P(A')=1-P(A)]
= 1- (P(M)+P(S)- P(M∩S)) [∵P(A∪B)=P(A)+P(B)-P(A∩B)]
= 1- (0.80+0.60-0.45)
= 1- 0.95
= 0.05
hence, the probability that Helen does not get an A in either class= 0.05