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natali 33 [55]
2 years ago
14

Barbara wants to restore her '66 Mustang in 4 years. She puts $200 into an account every month that pays 4.5% interest, compound

ed monthly. How much is in the account after 4 years?
Mathematics
1 answer:
Tcecarenko [31]2 years ago
6 0

Answer:

$10496.77

Step-by-step explanation:

We have been given that Barbara puts $200 into an account every month that pays 4.5% interest, compounded monthly.

To find the money in the account after 4 years, we will use future value formula.  

FV=R(\frac{1+\frac{r}{n})^{nt}-1}{\frac{r}{n}}), where,

R = Regular deposits,

r = Interest rate in decimal form

n = Number of times interest in compounded per year,

t = Time in years.

4.5\%=\frac{4.5}{100}=0.045

Substitute given values:

FV=\$200(\frac{1+\frac{0.045}{12})^{12*4}-1}{\frac{0.045}{12}})

FV=\$200(\frac{1+0.00375)^{48}-1}{0.00375})

FV=\$200(\frac{1.00375)^{48}-1}{0.00375})

FV=\$200(1.1968143774194609-1}{0.00375})

FV=\$200(0.1968143774194609}{0.00375})

FV=\$200(52.4838339785229066667)

FV=\$10496.76679570458133334

FV\approx \$10496.77

Therefore, there will be an amount of $10496.77 in the account after 4 years.

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when a sample is selected in a manner that some elements, in this case patients, of population have higher or lower probability of sampling then that sample is biased.

From given case, all the following are biased samples

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Step-by-step explanation:

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A firm has a revenue function that can be represented by r (x)=700x-0.35x^2, where r (x) is the total revenue (in dollars) and x
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Answer:

How many units need to be sold to produce the maximum revenue? 1000 units

How many in dollars is the maximum revenue when the maximum of units are sold? $350,000

Step-by-step explanation:

We get max value of a function if we differentiate it and set it equal to 0.

We need to differentiate r(x) and set it equal to 0 and solve for x.

<u><em>That would be number of units sold to get max revenue.</em></u>

<u><em /></u>

<u>Then we take that "x" value and substitute into r(x) to get the max revenue amount.</u>

<u />

Before differentiating, we see the rules shown below:

f(x)=ax^n\\f'(x)=n*ax^{n-1}

Where

f'(x) is the differentiated function

Now, let's do the process:

r (x)=700x-0.35x^2\\r(x)=700-2*0.35x\\r(x)=700-0.7x\\0=700-0.7x\\0.7x=700\\x=1000

So, 1000 units need to be sold for max revenue

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The max revenue amount is $350,000

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