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2 years ago

14

Derive an equation d = acos(bt) for the displacement d (in feet) in relation to sea level of a piece of cloth tied to a water wh

eel over t seconds. Assume the water wheel is half-submerged and takes 24 seconds to complete one turn. At t = 0 seconds, the cloth is at a height of 10 feet above sea level, its maximum displacement from the surface of the water.
Find the values of a and b.

1 answer:

Alisiya [41]2 years ago

4 0

Answer:

hjjhbvbyj

Step-by-step explanation:

a=10

b=pi/12

d=10cos(pi/12t)

t=6

d=5

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Factoring is a step taken towards solving a quadratic equation. ... You cannot factor them, the only way to find the roots then, is by using the quadratic formula. Suppose you factor the quadratic polynomial as and . Then set them equal to zero and solve for , you will have

Step-by-step explanation.

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2 years ago

A company produces and sells 211,600 boxes of t-shirts each year. Each production run has a fixed cost of $400 and an additional

Illusion [34]

Answer: $x=46$

Step-by-step explanation:

Given

Company Produces and sells 211600 boxes of T-shirt each year

Fixed cost =$ 400

Additional cost = $ 3 per box

storage cost =$ 2

let x be the no of production run

therefore

Holding cost per year $=holding\ cost\times average\ holding\ items=2\times \frac{211600}{2x}=\frac{211600}{x}$

$Yearly\ ordering\ cost=cost\ during\ each\ order\times number\ of\ order\ Placed\ per\ year$

yearly ordering cost $=400x+3\times \frac{211600}{x}$

Total cost C(x) $=\frac{211600}{x}+400x+3\times \frac{211600}{x}$

differentiate C(x) w.r.t to x we get

$\frac{\mathrm{d} C(x)}{\mathrm{d} x}=400-\frac{3\times 211600}{x^2}-\frac{1}{211600}$

Put $\frac{\mathrm{d} C(x)}{\mathrm{d} x}=0$ to get max/min value

$400-\frac{211600}{x^2}-\frac{3\times 211600}{x^2}=0$

$x^2=\frac{211600}{100}$

$x=\sqrt{2116}$

$x=46$

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1 year ago

A construction company is considering submitting bids for contracts of three different projects. The company estimates that it h

julsineya [31]

Answer:

a. $P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}\\$

b. $E(x) = 0.3$

c. $S(x)=0.5196$

d. $E=5,000$

Step-by-step explanation:

The probability that the company won x bids follows a binomial distribution because we have n identical and independent experiments with a probability p of success and (1-p) of fail.

So, the PMF of X is equal to:

$P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}\\$

Where p is 0.1 and it is the chance of winning. Additionally, n is 3 and it is the number of bids. So the PMF of X is:

$P(x)=\frac{3!}{x!(3-x)!}*0.1^{x}*(1-0.1)^{n-x}\\$

For binomial distribution:

$E(x)=np\\S(x)=\sqrt{np(1-p)}$

Therefore, the company can expect to win 0.3 bids and it is calculated as:

$E(x) = np = 3*0.1 = 0.3$

Additionally, the standard deviation of the number of bids won is:

$S(x)=\sqrt{np(1-p)}=\sqrt{3(0.1)(1-0.1)}=0.5196$

Finally, the probability to won 1, 2 or 3 bids is equal to:

$P(1)=\frac{3!}{1!(3-1)!}*0.1^{1}*(1-0.1)^{3-1}=0.243\\P(2)=\frac{3!}{2!(3-2)!}*0.1^{2}*(1-0.1)^{3-2}=0.027\\P(3)=\frac{3!}{3!(3-3)!}*0.1^{3}*(1-0.1)^{3-3}=0.001$

So, the expected profit for the company is equal to:

$E=-10,000+50,000(0.243)+100,000(0.027)+150,000(0.001)\\E=5,000$

Because there is a probability of 0.243 to win one bid and it will produce 50,000 of income, there is a probability of 0.027 to win 2 bids and it will produce 100,000 of income and there is a probability of 0.001 to win 3 bids and it will produce 150,000 of income.

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2 years ago