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Sliva [168]
2 years ago
11

57:04 The cooking time for a mini-loaf of bread is 5 minutes longer than half the time it takes to bake a regular-sized loaf of

bread. If it takes 25 minutes to bake a mini-loaf, how long does it take to bake a regular-sized loaf? 10 minutes 20 minutes 30 minutes 40 minutes
Mathematics
2 answers:
svlad2 [7]2 years ago
6 0

Answer:

The answer would be C(30)

Step-by-step explanation:

25 + 5 =30

The question states that it takes 5 minutes longer to cook a larger loaf of bread then it does to make a mini loaf, the mini loaf took 25 minutes to cook, there for the answer would be 30.

Hope this helps

Please give me Brainliest

Vinvika [58]2 years ago
6 0

Answer:

the answer is 30

Step-by-step explanation:

because if The cooking time for a mini-loaf of bread is 5 minutes longer than half the time and it takes 25 minutes to bake a mini-loaf then you add well it makes sense to me

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Reza paid $4,500 as a down payment on a car. She then made equal monthly paments of $250. Reza paid a total of $10,500 for her c
monitta
10500-4500=6000

6000/250=24

So the answer is 24 months, or 2 years.
6 0
1 year ago
If angle AOB = 4x - 2 and BOC = 5x + 10 and COD = 2x + 14. What is x?
Softa [21]
Angle AOD = 180
4x-2 + 5x+10 + 2x+14 = 180
11x + 22 = 180
11x = 180 - 22 = 158
x = 158/11
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1 year ago
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On this map, Oxford Street is perpendicular to_______ , and Rosewood Street is perpendicular to ________. Assume that the street
melamori03 [73]
Hi there!

We are looking for perpendicular angles, which means the angle between the streets is 90 degrees. So, each time we need to find the street that intersects the given street with a 90 degree angle.

On this map, Oxford Street is perpendicular to Waterloo St., and Rosewood Street is perpendicular to Oak St..

The answers are (in correct order): Waterloo St. and Oak St..
~ Hope this helps you!
6 0
2 years ago
An investor believes that investing in domestic and international stocks will give a difference in the mean rate of return. They
arlik [135]

Answer:

So on this case the 90% confidence interval would be given by -4.137 \leq \mu_1 -\mu_2 \leq 2.087  

For this case since the confidence interval for the difference of means contains the 0 we can conclude that we don't have significant differences at 10% of significance between the two means analyzed.

Step-by-step explanation:

Previous concepts  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

\bar X_1 =2.0233 represent the sample mean 1  

\bar X_2 =3.048 represent the sample mean 2  

n1=15 represent the sample 1 size  

n2=15 represent the sample 2 size  

s_1 =4.893387 population sample deviation for sample 1  

s_2 =5.12399 population sample deviation for sample 2  

\mu_1 -\mu_2 parameter of interest at 0.1 of significance so the confidence would be 0.9 or 90%

We want to test:

H0: \mu_1 = \mu_2

H1: \mu_1 \neq \mu_2

And we can do this using the confidence interval for the difference of means.

Solution to the problem  

The confidence interval for the difference of means is given by the following formula:  

(\bar X_1 -\bar X_2) \pm t_{\alpha/2}\sqrt{\frac{s^2_1}{n_1}+\frac{s^2_2}{n_2}} (1)  

The point of estimate for \mu_1 -\mu_2 is just given by:  

\bar X_1 -\bar X_2 =2.0233-3.048=-1.0247

The degrees of freedom are given by:

df = n_1 +n_2 -2 = 15+15-2=28  

Since the Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.05,28)".And we see that t_{\alpha/2}=\pm 1.701  

Now we have everything in order to replace into formula (1):  

-1.0247-1.701\sqrt{\frac{4.893387^2}{15}+\frac{5.12399^2}{15}}=-4.137  

-1.0247+1.701\sqrt{\frac{4.893387^2}{15}+\frac{5.12399^2}{15}}=2.087  

So on this case the 90% confidence interval would be given by -4.137 \leq \mu_1 -\mu_2 \leq 2.087  

For this case since the confidence interval for the difference of means contains the 0 we can conclude that we don't have significant differences at 10% of significance between the two means analyzed.

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Murljashka [212]
X^2 = 81...take the square root of both sides, eliminating the ^2
x = (+-) sqrt 81
x = (+-) 9

answers are : -9 and 9
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