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Sliva [168]
2 years ago
11

57:04 The cooking time for a mini-loaf of bread is 5 minutes longer than half the time it takes to bake a regular-sized loaf of

bread. If it takes 25 minutes to bake a mini-loaf, how long does it take to bake a regular-sized loaf? 10 minutes 20 minutes 30 minutes 40 minutes
Mathematics
2 answers:
svlad2 [7]2 years ago
6 0

Answer:

The answer would be C(30)

Step-by-step explanation:

25 + 5 =30

The question states that it takes 5 minutes longer to cook a larger loaf of bread then it does to make a mini loaf, the mini loaf took 25 minutes to cook, there for the answer would be 30.

Hope this helps

Please give me Brainliest

Vinvika [58]2 years ago
6 0

Answer:

the answer is 30

Step-by-step explanation:

because if The cooking time for a mini-loaf of bread is 5 minutes longer than half the time and it takes 25 minutes to bake a mini-loaf then you add well it makes sense to me

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Mary was told that a line goes through the points (1, 3) and (6, -2) and has a slope of 3.
ki77a [65]

Answer:

a. The slope is incorrect

b. y = 3x, ( 0 , 0 )

c) y = 4 - x

Step-by-step explanation:

Given:-

The slope between two points (1, 3) and (6, -2) is 3.

a. Explain why the information Mary was given cannot be correct.

- The slope between two arbitrary points, ( x1 , y1 ) and  (x2 , y2) is given by the following relationship:

                         slope = ( y2 - y1 ) / ( x2 - x1)

- Use the given points (1, 3) and (6, -2) and determine the slope:

                        slope = ( -2 - 3 ) / ( 6 - 1 )

                        slope = ( -5 ) / ( 5 )

                        slope = -1

- Yes, the given slope is incorrect it should be = -1

b.If the given point (1, 3) and the given slope are correct, what is the equation for the line? Give the  coordinates of another point on the line

- We will assume the point (1,3) lies on line with a slope = 3.

- We will use the slope-intercept equation of line:

                              y = slope*x + c

Where,      m : Slope

                 c : y-intercept

                             y = 3x + c

Using the given correct point to evaluate the y-intercept (c):

                             3 = 3*1 + c

                             c = 0

- The equation of line is,

                            y = 3x

- The origin (0,0) lies on the line y = 3x.

c. If the given points are correct for the line, what is the slope? Write an equation for the line

- We will assume the points (1, 3) and (6, -2) lies on line with a slope calculated in part (a) to be = -1.

- We will use the slope-intercept equation of line:

                              y = slope*x + c

Where,      m : Slope

                 c : y-intercept

                             y = -x + c

Using the given points to evaluate the y-intercept (c):

                             3 = -1 + c

                             c = 4

- The equation of line is,

                            y = -x + 4

4 0
2 years ago
Merrill Lynch Securities and Health Care Retirement Inc. are two large employers in downtown Toledo, Ohio. They are considering
ratelena [41]

Answer:

Step-by-step explanation:

We would determine the mean an standard deviation first

Mean = (107 + 92 + 97 + 95 + 105 + 101 + 91 + 99 + 95 + 104)/10 = 98.6

Standard deviation = √(summation(x - mean)/n

n = 10

Summation(x - mean) = (107 - 98.6)^2 + (92 - 98.6)^2 + (97 - 96.6)^2 + (95 - 98.6)^2 + (105 - 98.6)^2 + (101 - 98.6)^2 + (91 - 98.6)^2 + (99 - 98.6)^2 + (95 - 98.6)^2 + (104 - 98.6)^2 = 274

Standard deviation = √(274/10) = 5.23

The confidence interval is used to determine the range of values that could possibly contain a population parameter (population mean)

Confidence interval is written in the form,

(Point estimate - margin of error, Point estimate + margin of error)

The sample mean, x is the point estimate for the population mean.

We will use the t distribution because the sample size is small and the population standard deviation is not given.

Degree of freedom, df = 10 - 1 = 9

α = 1 - 0.99 = 0.01

z α/2 = 0.01/2 = 0.005

The area to the right of z 0.005 is 0.005 and the area to the left of z0.005 is 1 - 0.005 = 0.995. Using the t distribution table,

z = 3.25

Margin of error = z × s/√n

Where

s = sample standard Deviation = 5.23

Margin of error = 3.25 × 5.23/√10 = 5.38

Confidence interval = sample mean(point estimate) ± z × σ/√n

The lower boundary of the confidence interval is

98.6 - 5.38 = 93.22

The upper boundary of the confidence interval is

98.6 + 5.38 = 103.98

We estimate with 99% confidence that the mean weekly child care cost of their employees is between $93.22 and $103.98

Also,

99% of the confidence intervals constructed in this way would contain the true value for the population mean of mean weekly child care cost of their employees.

6 0
2 years ago
The graph represents the piecewise function: f(x) = What is the domain and range of the function? Domain: Range:
White raven [17]

Answer:

domain: All real numbers

Range: all real numbers greater than or equal to 0

Step-by-step explanation:

Edge 2020

4 0
1 year ago
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How does this graph change between point D and point G?
Leona [35]

Answer:

i don't see the graph

Step-by-step explanation:

3 0
2 years ago
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If a cow has a mass of 9×102 kilograms, and a blue whale has a mass of 1.8×105 kilograms, which of these statements is true?
lana66690 [7]

Answer:

The mass of the Blue whale is 200 times the mass of the cow

Step-by-step explanation:

Given

Mass of Cow = 9 * 10² kg

Mass of Blue Whale = 1.8 * 10⁵ kg

Required

Determine the relationship between both weights

Represent the mass of the cow with C and the mass of the whale with B

C = 9 * 10^2kg

C = 9 *100kg

C = 900kg

B = 1.8 * 10^5kg

B = 1.8 * 100000kg

B = 180000kg

Divide the bigger weight by the smaller weight

\frac{B}{C} = \frac{180000kg}{900kg}

\frac{B}{C} = \frac{180000}{900}

\frac{B}{C} = {200}{}

Multiply both sides by C

C * \frac{B}{C} = {200}{} * C

B = {200}{} * C

B = 200}C

<em>From the expression above, it can be concluded that the mass of the Blue whale is 200 times the mass of the cow</em>

7 0
1 year ago
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