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2 years ago

12

Based only on the information given in the diagram which congruence theorems or postulates could be givenas reasons why triangle

JOY~LIM?
Check All That Apply.

A. LA
B. LL
C. HA
D. HL
E. AAS
F. ASA

2 answers:

Evgesh-ka [11]2 years ago

3 0

The answer is C, E, and F on Apex

Volgvan2 years ago

3 0

C, E, and F.

You'r"e welcOme/

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A store sells both cold and hot beverages. Cold beverages, c, cost $1.50, while hot beverages, h, cost $2.00. On Saturday, drink

Marina86 [1]

2h + 4h (1.5c) = 360 so option b is correct.

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With reference to the figure match the angles and arcs to their measures

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Angle BAC = (180 - 114) degrees = 66 degrees [angle on a straight line]

Angle OCA = Angle OBA = 90 degrees    [angle at the point where the tangent and the radius meet]

Thus, the measure of arc BC = (360 - 66 - 90 - 90) degrees = 114 degrees [sum of interior angles of a quadrilateral]

Angle CDE = (180 - 124) degrees = 56 degrees [angle on a straight line]

Angle OCD = Angle OED = 90 degrees    [angle at the point where the tangent and the radius meet]

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Thus, angle BFE = (360 - 122 - 90 - 90) degrees = 58 degrees.

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2 years ago

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The probability of a golden retriever catching a tennis ball in mid-air is 74%. Find the probability that a golden retriever cat

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Answer:

Step-by-step explanation:

Given a large enough sample size the probability is 100%

If the question is "What is the probability of catching 3 tennis balls in three tosses in mid air. Sample size is 3

0.74³ = 0.405224 or about 41%

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1 year ago

A certain temperature measurement is performed 500 times. The mean value is 0 deg F and the standard deviation is 1 deg F. Assum

egoroff_w [7]

Answer:

477

Step-by-step explanation:

Given that:

Number of trials (n) = 500

Mean (m) = 0

Standard deviation (s) = 1

how many readings fall within +/- 2.000 deg F of the mean value

Mean of 0 and standard deviation of 1

P(-2 ≤ x ≤ 2)

Using the Z probability calculator :

P(x ≤ 2) = 0.97725 ;

P(x ≤ - 2) = 0.02275

Hence :

P(x ≤ 2) - P(x ≤ - 2) = 0.97725 - 0.02275 = 0.9545

Hence, number of readings in 500 trials:

0.9545 * 500 = 477.25

= 477 values

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1 year ago

A sample of 1714 cultures from individuals in Florida diagnosed with a strep infection was tested for resistance to the antibiot

Damm [24]

Answer:

a) $p$ represent the real population proportion of people who showed partial or complete resistance to the antibiotic

b) $\hat p=\frac{973}{1714}=0.568$ represent the estimated proportion of people who showed partial or complete resistance to the antibiotic

c) We are confident (95%) that the true proportion of individuals in Florida diagnosed with a strep infection was tested for resistance to the antibiotic penicillin present partial or complete resistance to the antibiotic is between 54.5% to 59.1%.

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Part a

Description in words of the parameter p

$p$ represent the real population proportion of people who showed partial or complete resistance to the antibiotic

$\hat p$ represent the estimated proportion of people who showed partial or complete resistance to the antibiotic

n=1714 is the sample size required

$z_{\alpha/2}$ represent the critical value for the margin of error

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Part b

Numerical estimate for p

In order to estimate a proportion we use this formula:

$\hat p =\frac{X}{n}$ where X represent the number of people with a characteristic and n the total sample size selected.

$\hat p=\frac{973}{1714}=0.568$ represent the estimated proportion of people who showed partial or complete resistance to the antibiotic

Part c

The confidence interval for a proportion is given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

And replacing into the confidence interval formula we got:

$0.568 - 1.96 \sqrt{\frac{0.568(1-0.568)}{1714}}=0.545$

$0.568 + 1.96 \sqrt{\frac{0.56(1-0.56)}{1714}}=0.591$

And the 95% confidence interval would be given (0.545;0.591).

We are confident that about 54.5% to 59.1% of individuals in Florida diagnosed with a strep infection was tested for resistance to the antibiotic penicillin present partial or complete resistance to the antibiotic.

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2 years ago