A new car is purchased for 23900 dollars. The value of the car depreciates at 9.25% per year. To the nearest tenth of a year, ho
2 answers:
9514 1404 393
Answer:
14.2 years
Step-by-step explanation:
The value is described by the exponential function ...
y = (initial value)·(decay factor)^x
where y is the value after x years.
The decay factor is (1 - annual depreciation) = 1 - 0.0925 = 0.9075, so we want to find x when ...
6000 = 23900·0.9075^x
6000/23900 = 0.9075^x . . . . . . . . . . . . . . divide by 23900
log(6000/23900) = x·log(0.9075) . . . . . . . take logarithms
x = log(6000/23900)/log(0.9075) ≈ 14.2396
It will be about 14.2 years until the value of the car is $6000.
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Answer:
The probability distribution is
X : 0 1 2
f(X) : 2/7 4/7 1/7
Step-by-step explanation:
Let x is the number of defective sets purchased by the hotel.
Total number of television sets = 7
Total number of defective television sets = 2
Since there are 2 defective television sets and hotel purchase 3 sets, So, X=0,1,2.
If X=0,
If X=1,
If X=2,
The probability distribution is
X : 0 1 2
f(X) : 2/7 4/7 1/7
The probability histogram is shown below.
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