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Arte-miy333 [17]
2 years ago
12

Amy is biking to school from her father's house and Jeremy is biking to school from his aunt's house. Suppose Amy is moving at a

rate 10 miles per hour and Jeremy is moving at a rate of 8 miles per hour. Can you assume that Amy will get to school first? Explain.
Mathematics
3 answers:
Snezhnost [94]2 years ago
7 0
Well, see the problem is... I don't know how far Amy's father house and Jeremy's aunt hose is from school. If they live on the same place, then I think Amy will come first. Be more clearer plz
sashaice [31]2 years ago
5 0
At first glance anyone would assume Amy would reach the school first because she is traveling at a faster rate. However, this is only true when both kids are in the same starting place. The question doesn't give us enough information to verify that answer because we don't know the location of the starting place. Perhaps Jeremy would reach the school first because his Aunt's house's closer to the school, even though he is traveling at a slower rate....
Guest1 year ago
0 0

No, having the greater rate of change does not mean a function will necessarily reach an output with the smallest input. It also depends on the initial values of the functions. If Jeremy's aunt lives closer to school, Jeremy's rate of change is smaller, but he could still get to school before Amy.

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Coordinates, gradient and tangent work (see image).
Ivenika [448]

Answer:

a) P(x,2x^2-5),\ Q(x+h,2(x+h)^2-5)

b) 4x+2h

c) 4x

Step-by-step explanation:

Given the curve

y=2x^2-5

a) If the x-coordinate of P is x, then the y-coordinate is 2x^2-5, so point P has coordinates (x,2x^2-5)

If the x-coordinate of Q is x+h, then the y-coordinate is 2(x+h)^2-5 so point Q has coordinates (x+h,2(x+h)^2-5)

b) The gradient of the secant RQ is

\dfrac{y_Q-y_P}{x_Q-x_P}\\ \\=\dfrac{(2(x+h)^2-5)-(2x^2-5)}{(x+h)-x}\\ \\=\dfrac{2(x+h)^2-5-x^2+5}{x+h-x}\\ \\=\dfrac{2(x+h)^2-2x^2}{h}\\ \\=\dfrac{2x^2+4xh+2h^2-2x^2}{h}\\ \\=\dfrac{4xh+2h^2}{h}\\ \\=4x+2h

c) If h\rightarrow 0, then the gradient 4x+2h\rightarrow 4x

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2 years ago
Ron and amie opened an educational savings account for their daughter when she was born making a $5,000 initial investment. They
Arlecino [84]

Interest rate= 0.083%

Step-by-step explanation:

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2 years ago
Q1: Identify the graph of the equation and write an equation of the translated or rotated graph in general form.
marin [14]

Answer:

C. hyperbola; 9x^2-25y^2-250y-850=0

Step-by-step explanation:

The given conic has equation:

9x^2-25y^2=225

Divide through by 225.

\frac{9x^2}{225}-\frac{25y^2}{225}=\frac{225}{225}

\frac{x^2}{25}-\frac{y^2}{9}=1

This is a hyperbola centered at the origin.

The hyperbola has been translated from the origin to (0,5).

The translated hyperbola will have equation;

\frac{(x-0)^2}{25}-\frac{(y-5)^2}{9}=1

Multiply through by 225.

9(x-0)^2-25(y-5)^2=225

Expand

9x^2-25(y^2-10y+25)=225

9x^2-25y^2+250y-625=225

Rewrite in general form;

9x^2-25y^2+250y-625-225=0

9x^2-25y^2+250y-850=0

3 0
2 years ago
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