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1 year ago

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In Boston taxicabs charge an initial fare and an additional amount for every mile traveled. Tahira is having trouble figuring ou

t how the system works. She paid $7.00 for a two-mike ride one day and she paid $24.50 for a nine-mule ride the next day. Use the data given to find the amount the taxis charge per mile

1 answer:

nlexa [21]1 year ago

3 0

Answer:

The taxi charges $2.5 for every mile.

Step-by-step explanation:

We are given the following in the question:

Let x be the initial taxicab fare and y be the additional amount for every mile traveled.

Cost for a two mile ride = $7.00

Thus, we can write the equation:

$x + 2y = 7$

Cost of a nine mile ride = $24.50

Thus, we can write the equation,

$x + 9y = 24.50$

Solving the two equation by elimination method, we have,

$x + 9y - (x + 2y) = 24.50 - 7\\7y = 17.5\\y = 2.5\\\Rightarrow x + 2(2.5) = 7\\x = 2$

Thus, $2 is the initial fare and $2.5 is the cost for every mile traveled.

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Weiming, Farhan and Sam had some comic books.

mixas84 [53]

Answer:

Farhan had 9 comic books

Sam had 51 comic books and lived in his Mother's basement

Step-by-step explanation:

W + F = 36

W = 3F

3F + F = 36

F = 9

W = 27

S + F = 60

S + 9 = 60

S = 51

5 0

1 year ago

Ben and Josh went to the roof of their 40-foot tall high school to throw their math books offthe edge.The initial velocity of Be

Taya2010 [7]

Answer

Josh's textbook reached the ground first

Josh's textbook reached the ground first by a difference of $t=0.6482$

Step-by-step explanation:

Before we proceed let us re write correctly the height equation which in correct form reads:

$h(t)=-16t^2 +v_{o}t+s$ Eqn(1).

Where:

$h(t)$ : is the height range as a function of time

$v_{o}$ : is the initial velocity

$s$ : is the initial heightin feet and is given as 40 feet, thus Eqn(1). becomes:

$h(t)=-16t^2 + v_{o}t + 40$ Eqn(2).

Now let us use the given information and set up our equations for Ben and Josh.

<u>Ben:</u>

We know that $v_{o}=60ft/s$

Thus Eqn. (2) becomes:

$h(t)=-16t^2+60t+40$ Eqn.(3)

<u>Josh:</u>

We know that $v_{o}=48ft/s$

Thus Eqn. (2) becomes:

$h(t)=-16t^2+48t+40$ Eqn. (4).

<em><u>Now since we want to find whose textbook reaches the ground first and by how many seconds we need to solve each equation (i.e. Eqns. (3) and (4)) at </u></em> $h(t)=0$ <em><u>. Now since both are quadratic equations we will solve one showing the full method which can be repeated for the other one. </u></em>

Thus we have for Ben, Eqn. (3) gives:

$h(t)=0-16t^2+60t+40=0$

Using the quadratic expression to find the roots of the quadratic we have:

$t_{1,2}=\frac{-b+/-\sqrt{b^2-4ac} }{2a} \\t_{1,2}=\frac{-60+/-\sqrt{60^2-4(-16)(40)} }{2(-16)} \\t_{1,2}=\frac{-60+/-\sqrt{6160} }{-32} \\t_{1,2}=\frac{15+/-\sqrt{385} }{8}\\\\t_{1}=4.3276 sec\\t_{2}=-0.5776 sec$

Since time can only be positive we reject the $t_{2}$ solution and we keep that Ben's book took $t=4.3276$ seconds to reach the ground.

Similarly solving for Josh we obtain

$t_{1}=3.6794sec\\t_{2}=-0.6794sec$

Thus again we reject the negative and keep the positive solution, so Josh's book took $t=3.6794$ seconds to reach the ground.

Then we can find the difference between Ben and Josh times as

$t_{Ben}-t_{Josh}= 4.3276 - 3.6794 = 0.6482$

So to answer the original question:

<em>Whose textbook reaches the ground first and by how many seconds?</em>

Josh's textbook reached the ground first
Josh's textbook reached the ground first by a difference of $t=0.6482$

3 0

1 year ago

Explain how knowing 1+7 helps you find the sum for7+1

ss7ja [257]

1+7 and 7+1 are the same equations. The numbers are just switched around .
Example:
1+2=3
2+1+3

<span>They add up to the same answer no matter where they are placed, therefore knowing 1+7 helps you find the sum of 7+1 (again, because they are the same) </span>

8 0

1 year ago

In an athletics team, tall members are three times more likely to win a medal than short members. this year the team has won 60

nirvana33 [79]

Well lets say y = the amount of medals won. lets say x is the amount won by short people and z is the amount won by tall. we know that the total medals is the total medals won by short and tall so:
y = x + z

it says that tall people are 3.times more likely. this would mean they won three times more than short people. so
z = 3x.

so if we know what z equals, we can replace z with what it is equal to. so:
y = x + z
y = x + 3x
y = 4x

we know that 60 medals were won so
y = 4x
60 = 4x
x = 15

that is the amount won by short people

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1 year ago

The following data shows the low temperature in Vancouver, in degrees Celsius, for two weeks in January one year. 8.90, 8.35, 8.

frutty [35]

There is no option of the box plots, so I have created a version that would represent this data.

To make the box plot you will need the lower extreme, lower quartile, median, upper quartile, and upper extreme.

Please see the attached picture.

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1 year ago