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Ronch [10]
2 years ago
14

What is StartFraction 11 Over 12 EndFraction divided by one-third? A fraction bar labeled 1. Under the 1 are 3 boxes labeled one

-third. Under the 3 boxes are 4 boxes containing one-fourth. Under the 4 boxes are 12 boxes containing StartFraction 1 Over 12 EndFraction. 2 and one-fourth 2 and three-fourths 3 and one-third 3 and two-thirds
Mathematics
2 answers:
Sav [38]2 years ago
8 0

Answer:

<h2>2 and three-fourths </h2>

Step-by-step explanation:

Given the expression \frac{11}{12}/\frac{1}{3}, the equivalent expression can be gotten as shown;

= \frac{11}{12}/\frac{1}{3}\\= \frac{11}{12}*\frac{3}{1}\\  = \frac{11}{4} \\= 2+\frac{3}{4}\\ = 2\frac{3}{4}

2 and three-fourth therefore gives the required expression

kow [346]2 years ago
5 0

Answer:

2 and three-fourths

Step-by-step explanation:

Given the expression , the equivalent expression can be gotten as shown;

Step-by-step explanation:

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Let’s play Pick-A-Ball with replacement! There are 10 colored balls: 3 red, 4 white, and 3 blue. The balls have been placed into
Anettt [7]

Answer:

0.48

Step-by-step explanation:

There are 10 colored balls: 3 red, 4 white, and 3 blue.

You selected 2 balls at random. They may be

RR, WW, BB, RW, RB, WB, WR, BR, BW.

To find the probability of selecting the color of ball that you just selected, find this probability in each of previous cases:

RR: (One red ball left and 8 balls left in total)

P_{RR}=\dfrac{3}{10}\cdot \dfrac{2}{9}\cdot \dfrac{1}{8}=\dfrac{1}{120}

WW: (Two white balls left and 8 balls left in total)

P_{WW}=\dfrac{4}{10}\cdot \dfrac{3}{9}\cdot \dfrac{2}{8}=\dfrac{1}{30}

BB: (One blue ball left and 8 balls left in total)

P_{BB}=\dfrac{3}{10}\cdot \dfrac{2}{9}\cdot \dfrac{1}{8}=\dfrac{1}{120}

RW: (Two red and three white balls left and 8 balls left in total)

P_{RW}=\dfrac{3}{10}\cdot \dfrac{4}{9}\cdot \dfrac{5}{8}=\dfrac{1}{12}

RB: (Two red and two blue balls left and 8 balls left in total)

P_{RB}=\dfrac{3}{10}\cdot \dfrac{3}{9}\cdot \dfrac{4}{8}=\dfrac{1}{20}

WB: (Two blue and three white balls left and 8 balls left in total)

P_{WB}=\dfrac{4}{10}\cdot \dfrac{3}{9}\cdot \dfrac{5}{8}=\dfrac{1}{12}

WR: (Two red and three white balls left and 8 balls left in total)

P_{WR}=\dfrac{4}{10}\cdot \dfrac{3}{9}\cdot \dfrac{5}{8}=\dfrac{1}{12}

BR: (Two red and two blue balls left and 8 balls left in total)

P_{BR}=\dfrac{3}{10}\cdot \dfrac{3}{9}\cdot \dfrac{4}{8}=\dfrac{1}{20}

BW: (Two blue and three white balls left and 8 balls left in total)

P_{BW}=\dfrac{4}{10}\cdot \dfrac{3}{9}\cdot \dfrac{5}{8}=\dfrac{1}{12}

In total, the probability of selecting the color of ball that you just selected is

\dfrac{1}{120}+\dfrac{1}{30}+\dfrac{1}{120}+2\cdot\dfrac{1}{12}+2\cdot \dfrac{1}{20}+2\cdot \dfrac{1}{12}=\\ \\=\dfrac{1}{120}+\dfrac{4}{120}+\dfrac{1}{120}+\dfrac{20}{120}+\dfrac{12}{120}+\dfrac{20}{120}=\dfrac{58}{120}=\dfrac{29}{60}\approx 0.48

3 0
1 year ago
In a random sample of 130 students, only 7 had been placed in the wrong math class. What is the best point estimate for the prop
Ivenika [448]
We have the given  in the problem as mentioned:
A total of 130 students and only 7 had been placed in the wrong math class.
With this given, we can easily draw the proportion of all students who have been placed in the wrong math class by estimation method and the solution is shown below:

Proportion = 7/130
5 0
1 year ago
Compute i^1+i^2+i^3....i^99+i^100
fgiga [73]

Good morning ☕️

Answer:

<h3>i¹ + i² + i³ +. . .+ i⁹⁹ + i¹⁰⁰ = 0</h3>

Step-by-step explanation:

Consider the sum S = i¹ + i² + i³ +. . .+ i⁹⁹ + i¹⁰⁰

S =  i¹ +  i² +  i³ + . . . + i⁹⁹  +  i¹⁰⁰

S = a₁ + a₂ + a₃ +. . . + a₉₉ + a₁₀₀

then, S is the sum of 100 consecutive terms of a geometric sequence (an)

where the first term a1 = i¹ = i  and the common ratio = i

FORMULA:______________________

S=(term1)*\frac{1-(common.ratio)^{number.of.terms}}{1-(common.ratio)}

_______________________________

then

S=i*\frac{1-i^{100} }{1-i}

or i¹⁰⁰ = (i⁴)²⁵ = 1²⁵ = 1  (we know that i⁴ = 1)

Hence

S = 0

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2 years ago
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Pls. see attachment. 

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1 year ago
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Answer: C

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8 0
1 year ago
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