Hello there,
To find out the equation you use the slope intercept form...
y = mx + b
M is the slope and b is where the line crosses the y-axis...
Now to find the slope you count the distance from two points so...
The distance from (0,2) to (1,5) is 3 units up and 1 unit over.
So the correct answer should be...
y = 3x + 2
Answer: w = 3z + 2
Hope I helped!!
-Char
<u>Complete Question</u>
The circle is inscribed in triangle PRT. A circle is inscribed in triangle P R T. Points Q, S, and U of the circle are on the sides of the triangle. Point Q is on side P R, point S is on side R T, and point U is on side P T. The length of R S is 5, the length of P U is 8, and the length of U T is 6. Which statements about the figure are true?
Answer:
(B)TU ≅ TS
(D)The length of line segment PR is 13 units.
Step-by-step explanation:
The diagram of the question is drawn for more understanding,
The theorem applied to this problem is that of tangents. All tangents drawn to a circle from the same point are equal.
Therefore:
|PQ|=|PU|=8 Units
|ST|=|UT| =6 Units
|RS|=|RQ|=5 Units
(b)From the above, TU ≅ TS
(d)Line Segment |PR|=|PQ|+|QR|=8+5=`13 Units
Answer:
The value of y is 6
units ⇒ 2nd answer
Step-by-step explanation:
In the attached figure
∵ ∠MTN is a right angle
∵ TU is the altitude of the triangle
- There are some rules in this triangle let us revise them
- (NT)² = NU . NM
- (MT)² = MU . MN
- (TU)² = MU . NU
- TM . TN = TU . MN
∵ NU = 9 units
∵ UM = 3 units
∵ MN = UM + NU
∴ MN = 3 + 9 = 12 units
- By using the 1st rule above
∴ (NT)² = 9 × 12
∴ (NT)² = 108
- Take a square root to both sides
∴ NT =
- Simplify the root
∴ NT = 6
units
∵ NT is y
∴ y = 6
units
The value of y is 6
units