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dolphi86 [110]
2 years ago
5

Find a function of the form y=Asin(kx)+C or y=Acos(kx)+C whose graph matches the function shown. ( in the picture)

Mathematics
2 answers:
m_a_m_a [10]2 years ago
4 0

Answer:

Your answer is: y = -3cosπ /2 - 3

​  

Step-by-step explanation:

We learned this last semester in pre calculus lol XD

Ivenika [448]2 years ago
4 0

Answer:

The required function is y=\sin\left(\frac{\pi}{7}x\right)-3.

Step-by-step explanation:

From the given graph it is clear that the value of function is not extreme at x=0, so the required function is a sine function.

The general form of a sine function is

y=A\sin(kx)+C                 ..... (1)

where, A is amplitude, \frac{2\pi}{k} is period and C is midline.

From the given graph it is clear that the maximum value of the function is -2 and minimum value of the function is -4.

Amplitude=\frac{Maximum-Minimum}{2}

Amplitude=\frac{-2-(-4)}{2}=1

Midline=\frac{Maximum+Minimum}{2}

Midline=\frac{-2+(-4)}{2}=-3

The function complete a cycle in 14 units, so period of the function is 14.

\frac{2\pi}{k}=14

\frac{2\pi}{14}=k

\frac{\pi}{7}=k

Substitute A=1, k=\frac{\pi}{7} and C=-3 in equation (1).

y=(1)\sin(\frac{\pi}{7}x)+(-3)

y=\sin\left(\frac{\pi}{7}x\right)-3

Therefore the required function is y=\sin\left(\frac{\pi}{7}x\right)-3.

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Write a real world problem that can be represented by the equation 3/4c=21
Black_prince [1.1K]

Answer: Real world problem is "A student have c toffee he distribute \frac{3}{4}th part of those toffees to his friends. He gave total 21 toffees to his friend".

Explanation:

Let a student have c number of toffees in his bag.

It is given that he distribute \frac{3}{4}th part of those toffees to his friends.

The \frac{3}{4}th part of c toffees is,

\frac{3c}{4}

The total number of distributed toffees is 21.

\frac{3c}{4}=21

It is the same as given equation.

If we change the equation in words it means the \frac{3}{4}th part of a number c is 21.

4 0
2 years ago
Read 2 more answers
Times for an ambulance to respond to a medical emergency in a certain town are normally distributed with a mean of 400 seconds a
garri49 [273]

Answer:

Step-by-step explanation:

In the normal distribution curve, the mean is in the middle and each line to the left and to the right of that mean represent 1- and 1+ the standard deviation.  If our mean is 400, then 400 + 50 = 450; 450 + 50 = 500; 500 + 50 = 550.  Going from the mean to the left, we subtract the standard deviation and 400 - 50 = 350; 350 - 50 = 300; 300 - 50 = 250.  We are interested in the range that falls between 350 and 450 as a percentage.  That range represents the two middle sections, each containing 34% of the data.  So the total percentage of response times is 68%.  We are looking then for 68% of the 144 emergency response times in town.  .68(144) = 97.92 or 98 emergencies that have response times of between 350 and 450 seconds.

7 0
2 years ago
Read 2 more answers
The domain of f(x) is the set os all real numbers greater than or equal to 0 and less than or equal to 2. True of false
sveticcg [70]

Answer:

True

Step-by-step explanation:

In Functions and Function Notation, we were introduced to the concepts of domain and range. In this section, we will practice determining domains and ranges for specific functions. Keep in mind that, in determining domains and ranges, we need to consider what is physically possible or meaningful in real-world examples, such as tickets sales and year in the horror movie example above. We also need to consider what is mathematically permitted. For example, we cannot include any input value that leads us to take an even root of a negative number if the domain and range consist of real numbers. Or in a function expressed as a formula, we cannot include any input value in the domain that would lead us to divide by 0.

Diagram of how a function relates two relations.

Figure 2

We can visualize the domain as a “holding area” that contains “raw materials” for a “function machine” and the range as another “holding area” for the machine’s products.

We can write the domain and range in interval notation, which uses values within brackets to describe a set of numbers. In interval notation, we use a square bracket [ when the set includes the endpoint and a parenthesis ( to indicate that the endpoint is either not included or the interval is unbounded. For example, if a person has $100 to spend, he or she would need to express the interval that is more than 0 and less than or equal to 100 and write

(

0

,

1

0

0

]

(0, 100]. We will discuss interval notation in greater detail later.

Let’s turn our attention to finding the domain of a function whose equation is provided. Oftentimes, finding the domain of such functions involves remembering three different forms. First, if the function has no denominator or an even root, consider whether the domain could be all real numbers. Second, if there is a denominator in the function’s equation, exclude values in the domain that force the denominator to be zero. Third, if there is an even root, consider excluding values that would make the radicand negative.

Before we begin, let us review the conventions of interval notation:

The smallest term from the interval is written first.

The largest term in the interval is written second, following a comma.

Parentheses, ( or ), are used to signify that an endpoint is not included, called exclusive.

Brackets, [ or ], are used to indicate that an endpoint is included, called inclusive.

The table below gives a summary of interval notation.

Summary of interval notation. Row 1, Inequality: x is greater than a. Interval notation: open parenthesis, a, infinity, close parenthesis. Row 2, Inequality: x is less than a. Interval notation: open parenthesis, negative infinity, a, close parenthesis. Row 3, Inequality x is greater than or equal to a. Interval notation: open bracket, a, infinity, close parenthesis. Row 4, Inequality: x less than or equal to a. Interval notation: open parenthesis, negative infinity, a, close bracket. Row 5, Inequality: a is less than x is less than b. Interval notation: open parenthesis, a, b, close parenthesis. Row 6, Inequality: a is less than or equal to x is less than b. Interval notation: Open bracket, a, b, close parenthesis. Row 7, Inequality: a is less than x is less than or equal to b. Interval notation: Open parenthesis, a, b, close bracket. Row 8, Inequality: a, less than or equal to x is less than or equal to b. Interval notation: open bracket, a, b, close bracket.

8 0
2 years ago
A gymnast dismounts the uneven parallel bars. Her height, h, depends on the time, t, that she is in the air h = −162 + 24t + 16.
dimulka [17.4K]
That is when h=0
so assuming yo meant
h(t)=-16t²+24t+16
solve for t such that h(t)=0
because when height=0, the gymnast hits the ground

so
0=-16t²+24t+16
using math (imma complete the square
0=-16(t²-3/2t)+16
0=-16(t²-3/2t+9/16-9/16)+16
0=-16((t-3/4)²-9/16)+16
0=-16(t-3/4)²+9+16
0=-16(t-3/4)²+25
-25=-16(t-3/4)²
25/16=(t-3/4)²
sqrt both sides
+/-5/4=t-3/4
3/4+/-5/4=t
if we do plus (because minus would give us negative height)
8/4=t
2=t
it takes 2 seconds
5 0
1 year ago
A survey of 132 students is selected randomly on a large university campus. They are asked if they use a laptop in class to take
ddd [48]

Answer:

For 90% CI = (0.428, 0.572)

For 98% CI = (0.399, 0.601)

The confidence interval (and Margin of error) reduces when 90% confidence level is used compared to when 98% confidence level is used.

Step-by-step explanation:

Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.

The confidence interval of a statistical data can be written as.

p+/-z√(p(1-p)/n)

Given that;

Proportion p = 66/132 = 0.50

Number of samples n = 132

Confidence level = 90%

z(at 90% confidence) = 1.645

Substituting the values we have;

0.50 +/- 1.645√(0.50(1-0.50)/132)

0.50 +/- 1.645√(0.001893939393)

0.50 +/- 0.071589436011

0.50 +/- 0.072

(0.428, 0.572)

The 90% confidence level estimate of the true population proportion of students who responded "yes" is (0.428, 0.572)

For 90% CI = (0.428, 0.572)

For 98% CI = (0.399, 0.601)

The confidence interval (and Margin of error) reduces when 90% confidence level is used compared to when 98% confidence level is used.

7 0
2 years ago
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