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dolphi86 [110]
2 years ago
5

Find a function of the form y=Asin(kx)+C or y=Acos(kx)+C whose graph matches the function shown. ( in the picture)

Mathematics
2 answers:
m_a_m_a [10]2 years ago
4 0

Answer:

Your answer is: y = -3cosπ /2 - 3

​  

Step-by-step explanation:

We learned this last semester in pre calculus lol XD

Ivenika [448]2 years ago
4 0

Answer:

The required function is y=\sin\left(\frac{\pi}{7}x\right)-3.

Step-by-step explanation:

From the given graph it is clear that the value of function is not extreme at x=0, so the required function is a sine function.

The general form of a sine function is

y=A\sin(kx)+C                 ..... (1)

where, A is amplitude, \frac{2\pi}{k} is period and C is midline.

From the given graph it is clear that the maximum value of the function is -2 and minimum value of the function is -4.

Amplitude=\frac{Maximum-Minimum}{2}

Amplitude=\frac{-2-(-4)}{2}=1

Midline=\frac{Maximum+Minimum}{2}

Midline=\frac{-2+(-4)}{2}=-3

The function complete a cycle in 14 units, so period of the function is 14.

\frac{2\pi}{k}=14

\frac{2\pi}{14}=k

\frac{\pi}{7}=k

Substitute A=1, k=\frac{\pi}{7} and C=-3 in equation (1).

y=(1)\sin(\frac{\pi}{7}x)+(-3)

y=\sin\left(\frac{\pi}{7}x\right)-3

Therefore the required function is y=\sin\left(\frac{\pi}{7}x\right)-3.

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Ronald finished his daily jog and wants a drink. In his refrigerator there are 2 cans of energy drink, 9 cans of soda, and 11 bo
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Answer:

P(water)=11/22=1/2

Step-by-step explanation:

The number of bottles with water is 11

The total number of bottles is 11 +9+2=22

Sothe probability that Ronald chooses a bottle of water is

P(water) =N(water)/N(total)=11/22=1/2

4 0
2 years ago
Jack is driving from his house to the airport. At 9:00 AM, he is 150 miles from the airport. At 10:30 AM, he is 75 miles from th
Jet001 [13]

Answer:

I b3live it is 50 miles/hour

Step-by-step explanation:

We need to know how many miles he drove from 9:00 to 10:30 so you do 150-75 which is 75. Then, you do 75÷1.5 because 9:00 and 10:30 are an hour and a half apart and then you get 50 mph.

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2 years ago
A circle has a circumference of 153.86153.86153, point, 86 units.
mariarad [96]
Answer=24.49 I’m not 100% sure but I believe this is the answer :)
Hope it helps
3 0
2 years ago
Read 2 more answers
1.Design a number line containing five (5) points 2.Benin, one of the smallest count pinstripes in Africa, has a total area of 4
gtnhenbr [62]
1.Design a number line containing five (5) points
 For this case what you should do is place a line with five points.
 You can think of one of the axes of the Cartesian plane, for example, the x-axis. We place five separate points in that line the same distance.
 line: 0 1 2 3 4 5

 a. Round off the total population to the nearest hundred thousand people
 nearest hundred thousand means
 100,000
 Then rounding off we have:
 10,160,555
 hundred thousand: 10,161,000 
 b. Round off Benin's area in square miles to the nearest thousand.

 nearest thousand means
 1,000
 Then rounding off we have:
 43,475
 thousand: 44,000

 Round off the number of miles of surfaced roads to the nearest ten. nearest ten means
 10
 Then rounding off we have:
 870
 ten: 870

d. Round off the number of people who live in rural areas to the nearest million
 nearest million means
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 3,657,790
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5 0
2 years ago
Read 2 more answers
Among a simple random sample of 331 American adults who do not have a four-year college degree and are not currently enrolled in
Hitman42 [59]

Answer:

(1) Therefore, a 90% confidence interval for the proportion of Americans who decide to not go to college because they cannot afford it is [0.4348, 0.5252].

(2) We can be 90% confident that the proportion of Americans who choose not to go to college because they cannot afford it is contained within our confidence interval

(3) A survey should include at least 3002 people if we wanted the margin of error for the 90% confidence level to be about 1.5%.

Step-by-step explanation:

We are given that a simple random sample of 331 American adults who do not have a four-year college degree and are not currently enrolled in school, 48% said they decided not to go to college because they could not afford school.

Firstly, the pivotal quantity for finding the confidence interval for the population proportion is given by;

                         P.Q.  =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of Americans who decide to not go to college = 48%

           n = sample of American adults = 331

           p = population proportion of Americans who decide to not go to

                 college because they cannot afford it

<em>Here for constructing a 90% confidence interval we have used a One-sample z-test for proportions.</em>

<em />

<u>So, 90% confidence interval for the population proportion, p is ;</u>

P(-1.645 < N(0,1) < 1.645) = 0.90  {As the critical value of z at 5% level

                                                        of significance are -1.645 & 1.645}  

P(-1.645 < \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } < 1.645) = 0.90

P( -1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < \hat p-p < 1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.90

P( \hat p-1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < p < \hat p+1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.90

<u>90% confidence interval for p</u> = [ \hat p-1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } , \hat p+1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ]

 = [ 0.48 -1.96 \times {\sqrt{\frac{0.48(1-0.48)}{331} } } , 0.48 +1.96 \times {\sqrt{\frac{0.48(1-0.48)}{331} } } ]

 = [0.4348, 0.5252]

(1) Therefore, a 90% confidence interval for the proportion of Americans who decide to not go to college because they cannot afford it is [0.4348, 0.5252].

(2) The interpretation of the above confidence interval is that we can be 90% confident that the proportion of Americans who choose not to go to college because they cannot afford it is contained within our confidence interval.

3) Now, it is given that we wanted the margin of error for the 90% confidence level to be about 1.5%.

So, the margin of error =  Z_(_\frac{\alpha}{2}_) \times \sqrt{\frac{\hat p(1-\hat p)}{n} }

              0.015 = 1.645 \times \sqrt{\frac{0.48(1-0.48)}{n} }

              \sqrt{n}  = \frac{1.645 \times \sqrt{0.48 \times 0.52} }{0.015}

              \sqrt{n} = 54.79

               n = 54.79^{2}

               n = 3001.88 ≈ 3002

Hence, a survey should include at least 3002 people if we wanted the margin of error for the 90% confidence level to be about 1.5%.

5 0
2 years ago
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