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2 years ago

15

A small cube with side length 6y is placed inside a larger cube with side length 4x^2. What is the difference in the volume of t

he cubes?

2 answers:

sleet_krkn [62]2 years ago

6 0

Answer:

$(64x^{6}-216y^{3})\ units^{3}$

Step-by-step explanation:

we know that

The volume of a cube is equal to

$V=s^{3}$

where

s is the length side of a cube

Step 1

Find the volume of the smaller cube

we have

$s=6y\ units$

substitute the value in the formula

$V1=(6y)^{3}=216y^{3}\ units^{3}$

Step 2

Find the volume of the larger cube

we have

$s=4x^{2}\ units$

substitute the value in the formula

$V2=(4x^{2})^{3}=64x^{6}\ units^{3}$

Step 3

Find the difference in the volume of the cubes

$V2-V1=(64x^{6}-216y^{3})\ units^{3}$

fomenos2 years ago

3 0

the different volume is the numbers. 4*2*6=?

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Step-by-step explanation:

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Now, we are finding the angle between $\times$ and vertical vector <0,0,1>

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nordsb [41]

Answer:

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Step-by-step explanation:

A segment whose length is 9 units.

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