Question

A small cube with side length 6y is placed inside a larger cube with side length 4x^2. What is the difference in the volume of the cubes?

Answer 1

Answer:

$(64x^{6}-216y^{3})\ units^{3}$

Step-by-step explanation:

we know that

The volume of a cube is equal to

$V=s^{3}$

where

s is the length side of a cube

Step 1

Find the volume of the smaller cube

we have

$s=6y\ units$

substitute the value in the formula

$V1=(6y)^{3}=216y^{3}\ units^{3}$

Step 2

Find the volume of the larger cube

we have

$s=4x^{2}\ units$

substitute the value in the formula

$V2=(4x^{2})^{3}=64x^{6}\ units^{3}$

Step 3

Find the difference in the volume of the cubes

$V2-V1=(64x^{6}-216y^{3})\ units^{3}$

Answer 2

the different volume is the numbers. 4*2*6=?