Answer: C
Step-by-step explanation:
48/64=3/4
a^(4-2)x b^(3-2)x c^(1-2)=a^2xb/c
Answer:
1/9; 4/9; 1/12; 1/6
Step-by-step explanation:
the probability that both numbers are greater than 6 if the same number can be chosen twice--> 3/9 * 3/9 = 1/9
the probability that both numbers are less than 7 if the same number can be chosen twice --> 6/9 * 6/9 = 4/9
the probability that both numbers are odd numbers less than 6 if the same numbers cannot be chosen twice --> 3/9 * 2/8 = 1/12
the probability that both numbers are even numbers if the same numbers cannot be chosen twice --> 4/9 * 3/8 = 1/6
Answer: P(A∪B)=0.72. The answer is provided below.
Step-by-step explanation:
Sue travels by bus or walks whenever she goes to the shops.
Probability of (catching the bus to shop ), P(A)= 0.4
Probability of (catching the bus from the shop ), P(B) = 0.7
Both of the events A and B are independent events.
Therefore, P(A∩B) = 0.4 × 0.7
= 0.28
Probability that Sue walks one way will be = 1 - P(A∩B)
= 1 - 0.28
= 0.72
Hence, the probability that Sue will walk at one way is 0.72
Answer:
20
Step-by-step explanation:
The expected value of a toss is:
E(X) = (0.10) (3) + (0.30) (1) + (0.60) (0)
E(X) = 0.6
If she scores an average of 0.6 points per toss, then the expected number of tosses needed to get 12 points is:
12 / 0.6 = 20
Using a random number table, we can assign digit 0 as a 3-point hole, digits 1-3 as a 1-point hole, and digits 4-9 as no points. Read the digits and add the points until you get 12 points. The number of digits read is the number of beanbag tosses.
